Whakaoti i te {-[(5/4)+(-2)]+(2/3)+(-1)^3+2*(4-3)}

$$\{ - [ ( \frac { 5 } { 4 } ) + ( - 2 ) ] + ( \frac { 2 } { 3 } ) + ( - 1 ) ^ { 3 } + 2 \cdot ( 4 - 3 ) \}$$

Aromātai

$$\frac{29}{12}\approx 2.416666667$$

Ngā Upane Otinga

Me tahuri te 2 ki te hautau \frac{8}{4}.

$$-\left(\frac{5}{4}-\frac{8}{4}\right)+\frac{2}{3}+\left(-1\right)^{3}+2\left(4-3\right)$$

Tā te mea he rite te tauraro o \frac{5}{4} me \frac{8}{4}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{5-8}{4}+\frac{2}{3}+\left(-1\right)^{3}+2\left(4-3\right)$$

Tangohia te 8 i te 5, ka -3.

$$-\left(-\frac{3}{4}\right)+\frac{2}{3}+\left(-1\right)^{3}+2\left(4-3\right)$$

Ko te tauaro o -\frac{3}{4} ko \frac{3}{4}.

$$\frac{3}{4}+\frac{2}{3}+\left(-1\right)^{3}+2\left(4-3\right)$$

Ko te maha noa iti rawa atu o 4 me 3 ko 12. Me tahuri \frac{3}{4} me \frac{2}{3} ki te hautau me te tautūnga 12.

$$\frac{9}{12}+\frac{8}{12}+\left(-1\right)^{3}+2\left(4-3\right)$$

Tā te mea he rite te tauraro o \frac{9}{12} me \frac{8}{12}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{9+8}{12}+\left(-1\right)^{3}+2\left(4-3\right)$$

Tāpirihia te 9 ki te 8, ka 17.

$$\frac{17}{12}+\left(-1\right)^{3}+2\left(4-3\right)$$

Tātaihia te -1 mā te pū o 3, kia riro ko -1.

$$\frac{17}{12}-1+2\left(4-3\right)$$

Me tahuri te 1 ki te hautau \frac{12}{12}.

$$\frac{17}{12}-\frac{12}{12}+2\left(4-3\right)$$

Tā te mea he rite te tauraro o \frac{17}{12} me \frac{12}{12}, me tango rāua mā te tango i ō raua taurunga.

$$\frac{17-12}{12}+2\left(4-3\right)$$

Tangohia te 12 i te 17, ka 5.

$$\frac{5}{12}+2\left(4-3\right)$$

Tangohia te 3 i te 4, ka 1.

$$\frac{5}{12}+2\times 1$$

Whakareatia te 2 ki te 1, ka 2.

$$\frac{5}{12}+2$$

Me tahuri te 2 ki te hautau \frac{24}{12}.

$$\frac{5}{12}+\frac{24}{12}$$

Tā te mea he rite te tauraro o \frac{5}{12} me \frac{24}{12}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{5+24}{12}$$

Tāpirihia te 5 ki te 24, ka 29.

$$\frac{29}{12}$$

Tauwehe

$$\frac{29}{2 ^ {2} \cdot 3} = 2\frac{5}{12} = 2.4166666666666665$$