Whakaoti i te [2-(1-0.5x2/3)]*[7+(-1)^3]

$$[ 2 - ( 1 - 0.5 x \frac { 2 } { 3 } ) ] \times [ 7 + ( - 1 ) ^ { 3 } ]$$

Aromātai

$$2\left(x+3\right)$$

Ngā Upane Otinga

Me tahuri ki tau ā-ira 0.5 ki te hautau \frac{5}{10}. Whakahekea te hautanga \frac{5}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$\left(2-\left(1-\frac{1}{2}x\times \frac{2}{3}\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Me whakarea te \frac{1}{2} ki te \frac{2}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\left(2-\left(1-\frac{1\times 2}{2\times 3}x\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Me whakakore tahi te 2 i te taurunga me te tauraro.

$$\left(2-\left(1-\frac{1}{3}x\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Hei kimi i te tauaro o 1-\frac{1}{3}x, kimihia te tauaro o ia taurangi.

$$\left(2-1-\left(-\frac{1}{3}x\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Ko te tauaro o -\frac{1}{3}x ko \frac{1}{3}x.

$$\left(2-1+\frac{1}{3}x\right)\left(7+\left(-1\right)^{3}\right)$$

Tangohia te 1 i te 2, ka 1.

$$\left(1+\frac{1}{3}x\right)\left(7+\left(-1\right)^{3}\right)$$

Tātaihia te -1 mā te pū o 3, kia riro ko -1.

$$\left(1+\frac{1}{3}x\right)\left(7-1\right)$$

Tangohia te 1 i te 7, ka 6.

$$\left(1+\frac{1}{3}x\right)\times 6$$

Whakamahia te āhuatanga tohatoha hei whakarea te 1+\frac{1}{3}x ki te 6.

$$6+\frac{1}{3}x\times 6$$

Whakareatia te \frac{1}{3} ki te 6, ka \frac{6}{3}.

$$6+\frac{6}{3}x$$

Whakawehea te 6 ki te 3, kia riro ko 2.

$$6+2x$$

Whakaroha

$$2x+6$$

Ngā Upane Otinga

Me tahuri ki tau ā-ira 0.5 ki te hautau \frac{5}{10}. Whakahekea te hautanga \frac{5}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 5.

$$\left(2-\left(1-\frac{1}{2}x\times \frac{2}{3}\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Me whakarea te \frac{1}{2} ki te \frac{2}{3} mā te whakarea taurunga ki te taurunga me te tauraro ki te tauraro.

$$\left(2-\left(1-\frac{1\times 2}{2\times 3}x\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Me whakakore tahi te 2 i te taurunga me te tauraro.

$$\left(2-\left(1-\frac{1}{3}x\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Hei kimi i te tauaro o 1-\frac{1}{3}x, kimihia te tauaro o ia taurangi.

$$\left(2-1-\left(-\frac{1}{3}x\right)\right)\left(7+\left(-1\right)^{3}\right)$$

Ko te tauaro o -\frac{1}{3}x ko \frac{1}{3}x.

$$\left(2-1+\frac{1}{3}x\right)\left(7+\left(-1\right)^{3}\right)$$

Tangohia te 1 i te 2, ka 1.

$$\left(1+\frac{1}{3}x\right)\left(7+\left(-1\right)^{3}\right)$$

Tātaihia te -1 mā te pū o 3, kia riro ko -1.

$$\left(1+\frac{1}{3}x\right)\left(7-1\right)$$

Tangohia te 1 i te 7, ka 6.

$$\left(1+\frac{1}{3}x\right)\times 6$$

Whakamahia te āhuatanga tohatoha hei whakarea te 1+\frac{1}{3}x ki te 6.

$$6+\frac{1}{3}x\times 6$$

Whakareatia te \frac{1}{3} ki te 6, ka \frac{6}{3}.

$$6+\frac{6}{3}x$$

Whakawehea te 6 ki te 3, kia riro ko 2.

$$6+2x$$