Whakaoti i te =600-40=50^circmm

$$= 600 - 40 = 50 ^ { \circ } mm$$

Whakaoti mō m

$$m = \frac{2 \sqrt{70}}{5} \approx 3.346640106$$

$$m = -\frac{2 \sqrt{70}}{5} \approx -3.346640106$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te m ki te m, ka m^{2}.

$$600-40=50m^{2}$$

Tangohia te 40 i te 600, ka 560.

$$560=50m^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$50m^{2}=560$$

Whakawehea ngā taha e rua ki te 50.

$$m^{2}=\frac{560}{50}$$

Whakahekea te hautanga \frac{560}{50} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 10.

$$m^{2}=\frac{56}{5}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$m=\frac{2\sqrt{70}}{5} m=-\frac{2\sqrt{70}}{5}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te m ki te m, ka m^{2}.

$$600-40=50m^{2}$$

Tangohia te 40 i te 600, ka 560.

$$560=50m^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$50m^{2}=560$$

Tangohia te 560 mai i ngā taha e rua.

$$50m^{2}-560=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 50 mō a, 0 mō b, me -560 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\times 50\left(-560\right)}}{2\times 50}$$

Pūrua 0.

$$m=\frac{0±\sqrt{-4\times 50\left(-560\right)}}{2\times 50}$$

Whakareatia -4 ki te 50.

$$m=\frac{0±\sqrt{-200\left(-560\right)}}{2\times 50}$$

Whakareatia -200 ki te -560.

$$m=\frac{0±\sqrt{112000}}{2\times 50}$$

Tuhia te pūtakerua o te 112000.

$$m=\frac{0±40\sqrt{70}}{2\times 50}$$

Whakareatia 2 ki te 50.

$$m=\frac{0±40\sqrt{70}}{100}$$

Nā, me whakaoti te whārite m=\frac{0±40\sqrt{70}}{100} ina he tāpiri te ±.

$$m=\frac{2\sqrt{70}}{5}$$

Nā, me whakaoti te whārite m=\frac{0±40\sqrt{70}}{100} ina he tango te ±.

$$m=-\frac{2\sqrt{70}}{5}$$

Kua oti te whārite te whakatau.

$$m=\frac{2\sqrt{70}}{5} m=-\frac{2\sqrt{70}}{5}$$