Whakaoti i te =-x^2+4x+5|x-x|/2

$$= - x ^ { 2 } + 4 x + \frac { 5 | x - x | } { 2 }$$

Aromātai

$$x\left(4-x\right)$$

Ngā Upane Otinga

Pahekotia te x me -x, ka 0.

$$-x^{2}+4x+\frac{5|0|}{2}$$

Ko te uara pū o tētahi tau tūturu a ko a ina a\geq 0, ko -a rānei ina a<0. Ko te uara pū o 0 ko 0.

$$-x^{2}+4x+\frac{5\times 0}{2}$$

Whakareatia te 5 ki te 0, ka 0.

$$-x^{2}+4x+\frac{0}{2}$$

Ko te kore i whakawehea ki te tau ehara te kore ka hua ko te kore.

$$-x^{2}+4x+0$$

Ko te tau i tāpiria he kore ka hua koia tonu.

$$-x^{2}+4x$$

Tauwehe

$$x\left(4-x\right)$$

Ngā Upane Otinga

Tauwehea te \frac{1}{2}.

$$\frac{-2x^{2}+8x}{2}$$

Whakaarohia te -2x^{2}+8x+5\left(x-x\right). Whakarea ka paheko i ngā kīanga tau ōrite.

$$-2x^{2}+8x$$

Whakaarohia te -2x^{2}+8x. Tauwehea te 2.

$$2\left(-x^{2}+4x\right)$$

Whakaarohia te -x^{2}+4x. Tauwehea te x.

$$x\left(-x+4\right)$$