Whakaoti i te =-[2/10b_{2}(2/10)+8/10log_{2}(8/10)]

$$= - [ \frac { 2 } { 10 } b _ { 2 } ( \frac { 2 } { 10 } ) + \frac { 8 } { 10 } \log _ { 2 } ( \frac { 8 } { 10 } ) ]$$

Aromātai

$$-\frac{b_{2}}{25}+\frac{4\log_{2}\left(5\right)}{5}-\frac{8}{5}$$

Ngā Upane Otinga

Whakareatia te \frac{2}{10} ki te \frac{2}{10}, ka \left(\frac{2}{10}\right)^{2}.

$$-\left(\left(\frac{2}{10}\right)^{2}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

Whakahekea te hautanga \frac{2}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$-\left(\left(\frac{1}{5}\right)^{2}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

Tātaihia te \frac{1}{5} mā te pū o 2, kia riro ko \frac{1}{25}.

$$-\left(\frac{1}{25}b_{2}+\frac{8}{10}\log_{2}\left(\frac{8}{10}\right)\right)$$

Whakahekea te hautanga \frac{8}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$-\left(\frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{8}{10}\right)\right)$$

Whakahekea te hautanga \frac{8}{10} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$-\left(\frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{4}{5}\right)\right)$$

Hei kimi i te tauaro o \frac{1}{25}b_{2}+\frac{4}{5}\log_{2}\left(\frac{4}{5}\right), kimihia te tauaro o ia taurangi.

$$-\frac{1}{25}b_{2}-\frac{4}{5}\log_{2}\left(\frac{4}{5}\right)$$

Tauwehe

$$\frac{-b_{2}+20\log_{2}\left(5\right)-40}{25}$$

Ngā Upane Otinga

Whakaarohia te \frac{1}{5}\times \frac{1}{5}b_{2}+\frac{4}{5}\ln(\frac{4}{5})\ln(2)^{-1}. Tauwehea te \frac{1}{25}.

$$\frac{b_{2}+20\log_{2}\left(\frac{4}{5}\right)}{25}$$

Me tuhi anō te kīanga whakatauwehe katoa. Whakarūnātia.

$$-\frac{b_{2}+20\log_{2}\left(\frac{4}{5}\right)}{25}$$