Whakaoti i te =(-2-0)^2*4/9+(0-0)^2*3/9+(1-0)^2*2/9

$$= ( - 2 - 0 ) ^ { 2 } \times \frac { 4 } { 9 } + ( 0 - 0 ) ^ { 2 } \times \frac { 3 } { 9 } + ( 1 - 0 ) ^ { 2 } \times \frac { 2 } { 9 }$$

Aromātai

$$2$$

Ngā Upane Otinga

Tangohia te 0 i te -2, ka -2.

$$\left(-2\right)^{2}\times \frac{4}{9}+\left(0-0\right)^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Tātaihia te -2 mā te pū o 2, kia riro ko 4.

$$4\times \frac{4}{9}+\left(0-0\right)^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Whakareatia te 4 ki te \frac{4}{9}, ka \frac{16}{9}.

$$\frac{16}{9}+\left(0-0\right)^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Mā te tango i te 0 i a ia ake anō ka toe ko te 0.

$$\frac{16}{9}+0^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Tātaihia te 0 mā te pū o 2, kia riro ko 0.

$$\frac{16}{9}+0\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Whakahekea te hautanga \frac{3}{9} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$\frac{16}{9}+0\times \frac{1}{3}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Whakareatia te 0 ki te \frac{1}{3}, ka 0.

$$\frac{16}{9}+0+\left(1-0\right)^{2}\times \frac{2}{9}$$

Tāpirihia te \frac{16}{9} ki te 0, ka \frac{16}{9}.

$$\frac{16}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Tangohia te 0 i te 1, ka 1.

$$\frac{16}{9}+1^{2}\times \frac{2}{9}$$

Tātaihia te 1 mā te pū o 2, kia riro ko 1.

$$\frac{16}{9}+1\times \frac{2}{9}$$

Whakareatia te 1 ki te \frac{2}{9}, ka \frac{2}{9}.

$$\frac{16}{9}+\frac{2}{9}$$

Tāpirihia te \frac{16}{9} ki te \frac{2}{9}, ka 2.

$$2$$

Tauwehe

$$2$$