Whakaoti i te =(330ton)(1.000kg/1ton)/(160g)(frac{1kg{1.000g})}xfrac{50text{pieces}}{1text{box}}

$$= \frac { ( 330 ton ) ( \frac { 1.000 kg } { 1 ton } ) } { ( 160 g ) ( \frac { 1 k g } { 1.000 g } ) } x \frac { 50 \text { pieces } } { 1 \text { box } }$$

Aromātai

$$\frac{33x}{16}$$

Ngā Upane Otinga

Me whakakore tahi te 1 i te taurunga me te tauraro.

$$\frac{330ton\times \frac{gk}{not}}{160g\times \frac{1kg}{1g}}x$$

Tuhia te 330\times \frac{gk}{not} hei hautanga kotahi.

$$\frac{\frac{330gk}{not}ton}{160g\times \frac{1kg}{1g}}x$$

Me whakakore tahi te g i te taurunga me te tauraro.

$$\frac{\frac{330gk}{not}ton}{160gk}x$$

Tuhia te \frac{330gk}{not}t hei hautanga kotahi.

$$\frac{\frac{330gkt}{not}on}{160gk}x$$

Me whakakore tahi te t i te taurunga me te tauraro.

$$\frac{\frac{330gk}{no}on}{160gk}x$$

Tuhia te \frac{330gk}{no}o hei hautanga kotahi.

$$\frac{\frac{330gko}{no}n}{160gk}x$$

Me whakakore tahi te o i te taurunga me te tauraro.

$$\frac{\frac{330gk}{n}n}{160gk}x$$

Me whakakore te n me te n.

$$\frac{330gk}{160gk}x$$

Me whakakore tahi te 10gk i te taurunga me te tauraro.

$$\frac{33}{16}x$$

Kimi Pārōnaki e ai ki x

$$\frac{33}{16} = 2\frac{1}{16} = 2.0625$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Me whakakore tahi te 1 i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{330ton\times \frac{gk}{not}}{160g\times \frac{1kg}{1g}}x)$$

Tuhia te 330\times \frac{gk}{not} hei hautanga kotahi.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\frac{330gk}{not}ton}{160g\times \frac{1kg}{1g}}x)$$

Me whakakore tahi te g i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\frac{330gk}{not}ton}{160gk}x)$$

Tuhia te \frac{330gk}{not}t hei hautanga kotahi.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\frac{330gkt}{not}on}{160gk}x)$$

Me whakakore tahi te t i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\frac{330gk}{no}on}{160gk}x)$$

Tuhia te \frac{330gk}{no}o hei hautanga kotahi.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\frac{330gko}{no}n}{160gk}x)$$

Me whakakore tahi te o i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{\frac{330gk}{n}n}{160gk}x)$$

Me whakakore te n me te n.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{330gk}{160gk}x)$$

Me whakakore tahi te 10gk i te taurunga me te tauraro.

$$\frac{\mathrm{d}}{\mathrm{d}x}(\frac{33}{16}x)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$\frac{33}{16}x^{1-1}$$

Tango 1 mai i 1.

$$\frac{33}{16}x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$\frac{33}{16}\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$\frac{33}{16}$$