Whakaoti i te +y^2-4x-2y-20=0

$$+ y ^ { 2 } - 4 x - 2 y - 20 = 0$$

Whakaoti mō x

$$x=\frac{y^{2}-2y-20}{4}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te y^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-4x-2y-20=-y^{2}$$

Me tāpiri te 2y ki ngā taha e rua.

$$-4x-20=-y^{2}+2y$$

Me tāpiri te 20 ki ngā taha e rua.

$$-4x=-y^{2}+2y+20$$

He hanga arowhānui tō te whārite.

$$-4x=20+2y-y^{2}$$

Whakawehea ngā taha e rua ki te -4.

$$\frac{-4x}{-4}=\frac{20+2y-y^{2}}{-4}$$

Mā te whakawehe ki te -4 ka wetekia te whakareanga ki te -4.

$$x=\frac{20+2y-y^{2}}{-4}$$

Whakawehe -y^{2}+2y+20 ki te -4.

$$x=\frac{y^{2}}{4}-\frac{y}{2}-5$$

Whakaoti mō y (complex solution)

$$y=\sqrt{4x+21}+1$$

$$y=-\sqrt{4x+21}+1$$

Whakaoti mō y

$$y=\sqrt{4x+21}+1$$

$$y=-\sqrt{4x+21}+1\text{, }x\geq -\frac{21}{4}$$