Atrisiniet 8y-8xy-8y^2=1

$$8 y - 8 x y - 8 y ^ { 2 } = 1$$

Atrast x

$$x=-y+1-\frac{1}{8y}$$

$$y\neq 0$$

Lineāra vienādojuma risināšanas darbības

Atņemiet 8y no abām pusēm.

$$-8xy-8y^{2}=1-8y$$

Pievienot 8y^{2} abās pusēs.

$$-8xy=1-8y+8y^{2}$$

Vienādojums ir standarta formā.

$$\left(-8y\right)x=8y^{2}-8y+1$$

Daliet abas puses ar -8y.

$$\frac{\left(-8y\right)x}{-8y}=\frac{8y^{2}-8y+1}{-8y}$$

Dalīšana ar -8y atsauc reizināšanu ar -8y.

$$x=\frac{8y^{2}-8y+1}{-8y}$$

Daliet 1-8y+8y^{2} ar -8y.

$$x=-y+1-\frac{1}{8y}$$

Atrast y (complex solution)

$$y=-\frac{\sqrt{4x^{2}-8x+2}}{4}-\frac{x}{2}+\frac{1}{2}$$

$$y=\frac{\sqrt{4x^{2}-8x+2}}{4}-\frac{x}{2}+\frac{1}{2}$$

Atrast y

$$y=-\frac{\sqrt{4x^{2}-8x+2}}{4}-\frac{x}{2}+\frac{1}{2}$$

$$y=\frac{\sqrt{4x^{2}-8x+2}}{4}-\frac{x}{2}+\frac{1}{2}\text{, }x\geq \frac{\sqrt{2}}{2}+1\text{ or }x\leq -\frac{\sqrt{2}}{2}+1$$