Atrisiniet 325=n[8b+(n-1)*(-3)/2

$$325 = \frac { n [ 8 b + ( n - 1 ) \times ( - 3 ) } { 2 }$$

Atrast b

$$b=\frac{3n}{8}-\frac{3}{8}+\frac{325}{4n}$$

$$n\neq 0$$

Lineāra vienādojuma risināšanas darbības

Reiziniet abas puses ar 2.

$$325\times 2=n\left(8b+\left(n-1\right)\times \left(-3\right)\right)$$

Reiziniet 325 un 2, lai iegūtu 650.

$$650=n\left(8b+\left(n-1\right)\times \left(-3\right)\right)$$

Izmantojiet distributīvo īpašību, lai reizinātu n ar 8b+\left(n-1\right)\times \left(-3\right).

$$650=8nb+n\left(\left(n-1\right)\times \left(-3\right)\right)$$

Mainiet puses tā, lai visi mainīgie locekļi atrastos pa kreisi.

$$8nb+n\left(\left(n-1\right)\times \left(-3\right)\right)=650$$

Atņemiet n\left(\left(n-1\right)\times \left(-3\right)\right) no abām pusēm.

$$8nb=650-n\left(\left(n-1\right)\times \left(-3\right)\right)$$

Pārkārtojiet locekļus.

$$8bn=-n\left(\left(n-1\right)\times \left(-3\right)\right)+650$$

Vienādojums ir standarta formā.

$$8nb=3n\left(n-1\right)+650$$

Daliet abas puses ar 8n.

$$\frac{8nb}{8n}=\frac{3n\left(n-1\right)+650}{8n}$$

Dalīšana ar 8n atsauc reizināšanu ar 8n.

$$b=\frac{3n\left(n-1\right)+650}{8n}$$

Daliet 3\left(n-1\right)n+650 ar 8n.

$$b=\frac{3n}{8}-\frac{3}{8}+\frac{325}{4n}$$

Atrast n (complex solution)

$$n=-\frac{\sqrt{64b^{2}+48b-7791}}{6}+\frac{4b}{3}+\frac{1}{2}$$

$$n=\frac{\sqrt{64b^{2}+48b-7791}}{6}+\frac{4b}{3}+\frac{1}{2}$$

Atrast n

$$n=-\frac{\sqrt{64b^{2}+48b-7791}}{6}+\frac{4b}{3}+\frac{1}{2}$$

$$n=\frac{\sqrt{64b^{2}+48b-7791}}{6}+\frac{4b}{3}+\frac{1}{2}\text{, }b\geq \frac{5\sqrt{78}}{4}-\frac{3}{8}\text{ or }b\leq -\frac{5\sqrt{78}}{4}-\frac{3}{8}$$