ແກ້ wfx=2x^2-3x+1/x+3

$$wfx = \frac{ 2 { x }^{ 2 } -3x+1 }{ x+3 }$$

ແກ້ສຳລັບ f (complex solution)

$$\left\{\begin{matrix}f=-\frac{\left(1-x\right)\left(2x-1\right)}{wx\left(x+3\right)}\text{, }&x\neq -3\text{ and }x\neq 0\text{ and }w\neq 0\\f\in \mathrm{C}\text{, }&\left(x=\frac{1}{2}\text{ or }x=1\right)\text{ and }w=0\end{matrix}\right,$$

ຂັ້ນຕອນສຳລັບການແກ້ສົມຜົນເສັ້ນຊື່

ຄູນທັງສອງຂ້າງຂອງສົມຜົນດ້ວຍ x+3.

$$wfx\left(x+3\right)=2x^{2}-3x+1$$

ໃຊ້ຄຸນສົມບັດການແຈກແຈງເພື່ອຄູນ wfx ດ້ວຍ x+3.

$$wfx^{2}+3wfx=2x^{2}-3x+1$$

ຮວມທຸກຄຳສັບທີ່ມີ f.

$$\left(wx^{2}+3wx\right)f=2x^{2}-3x+1$$

ຫານທັງສອງຂ້າງດ້ວຍ wx^{2}+3wx.

$$\frac{\left(wx^{2}+3wx\right)f}{wx^{2}+3wx}=\frac{\left(x-1\right)\left(2x-1\right)}{wx^{2}+3wx}$$

ການຫານດ້ວຍ wx^{2}+3wx ຈະຍົກເລີກການຄູນດ້ວຍ wx^{2}+3wx.

$$f=\frac{\left(x-1\right)\left(2x-1\right)}{wx^{2}+3wx}$$

ຫານ \left(-1+x\right)\left(-1+2x\right) ດ້ວຍ wx^{2}+3wx.

$$f=\frac{\left(x-1\right)\left(2x-1\right)}{wx\left(x+3\right)}$$

ແກ້ສຳລັບ w (complex solution)

$$\left\{\begin{matrix}w=-\frac{\left(1-x\right)\left(2x-1\right)}{fx\left(x+3\right)}\text{, }&x\neq -3\text{ and }x\neq 0\text{ and }f\neq 0\\w\in \mathrm{C}\text{, }&\left(x=\frac{1}{2}\text{ or }x=1\right)\text{ and }f=0\end{matrix}\right,$$

ຂັ້ນຕອນສຳລັບການແກ້ສົມຜົນເສັ້ນຊື່

ຄູນທັງສອງຂ້າງຂອງສົມຜົນດ້ວຍ x+3.

$$wfx\left(x+3\right)=2x^{2}-3x+1$$

ໃຊ້ຄຸນສົມບັດການແຈກແຈງເພື່ອຄູນ wfx ດ້ວຍ x+3.

$$wfx^{2}+3wfx=2x^{2}-3x+1$$

ຮວມທຸກຄຳສັບທີ່ມີ w.

$$\left(fx^{2}+3fx\right)w=2x^{2}-3x+1$$

ຫານທັງສອງຂ້າງດ້ວຍ 3xf+fx^{2}.

$$\frac{\left(fx^{2}+3fx\right)w}{fx^{2}+3fx}=\frac{\left(x-1\right)\left(2x-1\right)}{fx^{2}+3fx}$$

ການຫານດ້ວຍ 3xf+fx^{2} ຈະຍົກເລີກການຄູນດ້ວຍ 3xf+fx^{2}.

$$w=\frac{\left(x-1\right)\left(2x-1\right)}{fx^{2}+3fx}$$

ຫານ \left(-1+x\right)\left(-1+2x\right) ດ້ວຍ 3xf+fx^{2}.

$$w=\frac{\left(x-1\right)\left(2x-1\right)}{fx\left(x+3\right)}$$

ແກ້ສຳລັບ f

$$\left\{\begin{matrix}f=-\frac{\left(1-x\right)\left(2x-1\right)}{wx\left(x+3\right)}\text{, }&x\neq -3\text{ and }x\neq 0\text{ and }w\neq 0\\f\in \mathrm{R}\text{, }&\left(x=\frac{1}{2}\text{ or }x=1\right)\text{ and }w=0\end{matrix}\right,$$

ຂັ້ນຕອນສຳລັບການແກ້ສົມຜົນເສັ້ນຊື່

ຄູນທັງສອງຂ້າງຂອງສົມຜົນດ້ວຍ x+3.

$$wfx\left(x+3\right)=2x^{2}-3x+1$$

ໃຊ້ຄຸນສົມບັດການແຈກແຈງເພື່ອຄູນ wfx ດ້ວຍ x+3.

$$wfx^{2}+3wfx=2x^{2}-3x+1$$

ຮວມທຸກຄຳສັບທີ່ມີ f.

$$\left(wx^{2}+3wx\right)f=2x^{2}-3x+1$$

ຫານທັງສອງຂ້າງດ້ວຍ wx^{2}+3wx.

$$\frac{\left(wx^{2}+3wx\right)f}{wx^{2}+3wx}=\frac{\left(x-1\right)\left(2x-1\right)}{wx^{2}+3wx}$$

ການຫານດ້ວຍ wx^{2}+3wx ຈະຍົກເລີກການຄູນດ້ວຍ wx^{2}+3wx.

$$f=\frac{\left(x-1\right)\left(2x-1\right)}{wx^{2}+3wx}$$

ຫານ \left(-1+x\right)\left(-1+2x\right) ດ້ວຍ wx^{2}+3wx.

$$f=\frac{\left(x-1\right)\left(2x-1\right)}{wx\left(x+3\right)}$$

ແກ້ສຳລັບ w

$$\left\{\begin{matrix}w=-\frac{\left(1-x\right)\left(2x-1\right)}{fx\left(x+3\right)}\text{, }&x\neq -3\text{ and }x\neq 0\text{ and }f\neq 0\\w\in \mathrm{R}\text{, }&\left(x=\frac{1}{2}\text{ or }x=1\right)\text{ and }f=0\end{matrix}\right,$$

ຂັ້ນຕອນສຳລັບການແກ້ສົມຜົນເສັ້ນຊື່

ຄູນທັງສອງຂ້າງຂອງສົມຜົນດ້ວຍ x+3.

$$wfx\left(x+3\right)=2x^{2}-3x+1$$

ໃຊ້ຄຸນສົມບັດການແຈກແຈງເພື່ອຄູນ wfx ດ້ວຍ x+3.

$$wfx^{2}+3wfx=2x^{2}-3x+1$$

ຮວມທຸກຄຳສັບທີ່ມີ w.

$$\left(fx^{2}+3fx\right)w=2x^{2}-3x+1$$

ຫານທັງສອງຂ້າງດ້ວຍ 3xf+fx^{2}.

$$\frac{\left(fx^{2}+3fx\right)w}{fx^{2}+3fx}=\frac{\left(x-1\right)\left(2x-1\right)}{fx^{2}+3fx}$$

ການຫານດ້ວຍ 3xf+fx^{2} ຈະຍົກເລີກການຄູນດ້ວຍ 3xf+fx^{2}.

$$w=\frac{\left(x-1\right)\left(2x-1\right)}{fx^{2}+3fx}$$

ຫານ \left(-1+x\right)\left(-1+2x\right) ດ້ວຍ 3xf+fx^{2}.

$$w=\frac{\left(x-1\right)\left(2x-1\right)}{fx\left(x+3\right)}$$