ແກ້ t_{2}=frac{ln(frac{x_{m}}{x_{0}}-1)+(31)}{gamma_{0}}

$$t _ { 2 } = \frac { \ln ( \frac { x _ { m } } { x _ { 0 } } - 1 ) + ( 31 ) } { \gamma _ { 0 } }$$

ແກ້ສຳລັບ t_2

$$t_{2}=\frac{\ln(\frac{x_{m}-x_{0}}{x_{0}})+31}{\gamma _{0}}$$

$$\left(\gamma _{0}\neq 0\text{ and }x_{m}<x_{0}\text{ and }x_{0}<0\right)\text{ or }\left(\gamma _{0}\neq 0\text{ and }x_{m}>x_{0}\text{ and }x_{0}>0\right)$$

ແກ້ສຳລັບ x_0

$$x_{0}=\frac{x_{m}}{e^{t_{2}\gamma _{0}-31}+1}$$

$$\gamma _{0}\neq 0\text{ and }x_{m}\neq 0$$