ແກ້ f(x)=4/3-2x^2+3/3x^3-5 | ແກ້ໄຂ f(x)=4/3-2x^2+3/3x^3-5

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Polynomial

5 ບັນຫາທີ່ຄ້າຍຄືກັນກັບ:

ບັນຫາທີ່ຄ້າຍຄືກັນຈາກWeb Search

https://socratic.org/questions/how-do-you-find-the-vertical-horizontal-or-slant-asymptotes-for-3-2x-2-5x-3-3x-3

https://socratic.org/questions/how-do-you-graph-and-find-the-discontinuities-of-f-x-2x-2-1-2x-3-4x-2

https://socratic.org/questions/how-do-you-graph-f-x-2x-3-2x-2-x-3-9x-using-holes-vertical-and-horizontal-asympt

https://socratic.org/questions/how-do-you-graph-2x-2-3x-1-x-2-5x-4-using-asymptotes-intercepts-end-behavior

https://socratic.org/questions/is-f-x-4x-3-2x-2-x-3-x-2-increasing-or-decreasing-at-x-0

ແບ່ງປັນ

ສໍາເນົາຄລິບ

\frac{4\left(3x^{3}-5\right)}{3\left(3x^{3}-5\right)}-\frac{3\left(2x^{2}+3\right)}{3\left(3x^{3}-5\right)}

ເພື່ອເພີ່ມ ຫຼື ຫານນິພົດ, ໃຫ້ຂະຫຍາຍພວກມັນເພື່ອໃຫ້ຕົວຄູນມີຈຳນວນດຽວກັນ. ຈຳນວນຄູນທີ່ນິຍົມໜ້ອຍທີ່ສຸດຂອງ 3 ກັບ 3x^{3}-5 ແມ່ນ 3\left(3x^{3}-5\right). ຄູນ \frac{4}{3} ໃຫ້ກັບ \frac{3x^{3}-5}{3x^{3}-5}. ຄູນ \frac{2x^{2}+3}{3x^{3}-5} ໃຫ້ກັບ \frac{3}{3}.

\frac{4\left(3x^{3}-5\right)-3\left(2x^{2}+3\right)}{3\left(3x^{3}-5\right)}

ເນື່ອງຈາກ \frac{4\left(3x^{3}-5\right)}{3\left(3x^{3}-5\right)} ແລະ \frac{3\left(2x^{2}+3\right)}{3\left(3x^{3}-5\right)} ມີຕົວຫານດຽວກັນ, ໃຫ້ຫານພວກມັນໂດຍການຫານຈຳນວນທີ່ເປັນເສດໃນເລກເສດສ່ວນຂອງພວກມັນ.

\frac{12x^{3}-20-6x^{2}-9}{3\left(3x^{3}-5\right)}

ຄູນໃນເສດສ່ວນ 4\left(3x^{3}-5\right)-3\left(2x^{2}+3\right).

\frac{12x^{3}-29-6x^{2}}{3\left(3x^{3}-5\right)}

ຮວມຂໍ້ກຳນົດໃນ 12x^{3}-20-6x^{2}-9.