ແກ້ ax-b^3=a^3-bx

$$a x - b ^ { 3 } = a ^ { 3 } - b x$$

ແກ້ສຳລັບ a (complex solution)

$$a=\frac{-\sqrt{4x-3b^{2}}+b}{2}$$

$$a=\frac{\sqrt{4x-3b^{2}}+b}{2}$$

$$a=-b$$

ແກ້ສຳລັບ b (complex solution)

$$b=\frac{\sqrt{4x-3a^{2}}+a}{2}$$

$$b=-a$$

$$b=\frac{-\sqrt{4x-3a^{2}}+a}{2}$$

ແກ້ສຳລັບ a

$$\left\{\begin{matrix}\\a=-b\text{, }&\text{unconditionally}\\a=\frac{-\sqrt{4x-3b^{2}}+b}{2}\text{; }a=\frac{\sqrt{4x-3b^{2}}+b}{2}\text{, }&x\geq \frac{3b^{2}}{4}\end{matrix}\right,$$

ແກ້ສຳລັບ b

$$\left\{\begin{matrix}\\b=-a\text{, }&\text{unconditionally}\\b=\frac{-\sqrt{4x-3a^{2}}+a}{2}\text{; }b=\frac{\sqrt{4x-3a^{2}}+a}{2}\text{, }&x\geq \frac{3a^{2}}{4}\end{matrix}\right,$$