ແກ້ phi=(4500N*C^{-1})(12336*10^{-4}m^2)cos{tan^-1(185*10^-2m)/(frac{122{2}*10^-2m)}}

$$\phi = ( 4500 N \cdot C ^ { - 1 } ) ( 12336 \times 10 ^ { - 4 } m ^ { 2 } ) \cos \{ \tan ^ { - 1 } \frac { ( 185 \times 10 ^ { - 2 } m ) } { ( \frac { 122 } { 2 } \times 10 ^ { - 2 } m ) } \}$$

ແກ້ສຳລັບ N

$$N=\frac{5\sqrt{37946}Cϕ}{1693116m^{2}}$$

$$C\neq 0\text{ and }m\neq 0$$

ຂັ້ນຕອນສຳລັບການແກ້ສົມຜົນເສັ້ນຊື່

ຄູນ 4500 ກັບ 12336 ເພື່ອໃຫ້ໄດ້ 55512000.

$$ϕ=55512000NC^{-1}\times 10^{-4}m^{2}\cos(\arctan(\frac{185\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

ຄຳນວນ 10 ກຳລັງ -4 ແລະ ໄດ້ \frac{1}{10000}.

$$ϕ=55512000NC^{-1}\times \frac{1}{10000}m^{2}\cos(\arctan(\frac{185\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

ຄູນ 55512000 ກັບ \frac{1}{10000} ເພື່ອໃຫ້ໄດ້ \frac{27756}{5}.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{185\times 10^{-2}m}{\frac{122}{2}\times 10^{-2}m}))$$

ຄຳນວນ 10 ກຳລັງ -2 ແລະ ໄດ້ \frac{1}{100}.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{185\times \frac{1}{100}m}{\frac{122}{2}\times 10^{-2}m}))$$

ຄູນ 185 ກັບ \frac{1}{100} ເພື່ອໃຫ້ໄດ້ \frac{37}{20}.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{20}m}{\frac{122}{2}\times 10^{-2}m}))$$

ຫານ 122 ດ້ວຍ 2 ເພື່ອໄດ້ 61.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{20}m}{61\times 10^{-2}m}))$$

ຄຳນວນ 10 ກຳລັງ -2 ແລະ ໄດ້ \frac{1}{100}.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{20}m}{61\times \frac{1}{100}m}))$$

ຄູນ 61 ກັບ \frac{1}{100} ເພື່ອໃຫ້ໄດ້ \frac{61}{100}.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{20}m}{\frac{61}{100}m}))$$

ຍົກເລີກ m ທັງໃນຕົວເສດ ແລະ ຕົວຫານ.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{\frac{37}{20}}{\frac{61}{100}}))$$

ຫານ \frac{37}{20} ດ້ວຍ \frac{61}{100} ໂດຍການຄູນ \frac{37}{20} ໂດຍຕົວເລກທີ່ກັບກັນຂອງ \frac{61}{100}.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{37}{20}\times \frac{100}{61}))$$

ຄູນ \frac{37}{20} ກັບ \frac{100}{61} ເພື່ອໃຫ້ໄດ້ \frac{185}{61}.

$$ϕ=\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{185}{61}))$$

ສະຫຼັບຂ້າງເພື່ອໃຫ້ພົດຕົວແປທັງໝົດຢູ່ຂ້າງຊ້າຍຂອງເຄື່ອງໝາຍເທົ່າກັບ.

$$\frac{27756}{5}NC^{-1}m^{2}\cos(\arctan(\frac{185}{61}))=ϕ$$

ສົມຜົນຢູ່ໃນຮູບແບບມາດຕະຖານ.

$$\frac{27756\cos(\arctan(\frac{185}{61}))m^{2}}{5C}N=ϕ$$

ຫານທັງສອງຂ້າງດ້ວຍ \frac{27756}{5}C^{-1}m^{2}\cos(\arctan(\frac{185}{61})).

$$\frac{\frac{27756\cos(\arctan(\frac{185}{61}))m^{2}}{5C}N\times 5C}{27756\cos(\arctan(\frac{185}{61}))m^{2}}=\frac{ϕ\times 5C}{27756\cos(\arctan(\frac{185}{61}))m^{2}}$$

ການຫານດ້ວຍ \frac{27756}{5}C^{-1}m^{2}\cos(\arctan(\frac{185}{61})) ຈະຍົກເລີກການຄູນດ້ວຍ \frac{27756}{5}C^{-1}m^{2}\cos(\arctan(\frac{185}{61})).

$$N=\frac{ϕ\times 5C}{27756\cos(\arctan(\frac{185}{61}))m^{2}}$$

ຫານ ϕ ດ້ວຍ \frac{27756}{5}C^{-1}m^{2}\cos(\arctan(\frac{185}{61})).

$$N=\frac{5\sqrt{37946}Cϕ}{1693116m^{2}}$$

ແກ້ສຳລັບ C

$$\left\{\begin{matrix}C=\frac{846558\sqrt{37946}Nm^{2}}{94865ϕ}\text{, }&m\neq 0\text{ and }N\neq 0\text{ and }ϕ\neq 0\\C\neq 0\text{, }&m\neq 0\text{ and }ϕ=0\text{ and }N=0\end{matrix}\right,$$