ແກ້ log_{03}(x-1)<log_{009}(x-1)

$$\log _ { 03 } ( x - 1 ) < \log _ { 009 } ( x - 1 )$$

ປະເມີນ

ຂັ້ນຕອນການແກ້

ຄູນ 0 ກັບ 3 ເພື່ອໃຫ້ໄດ້ 0.

$$\log_{0}\left(x-1\right)<\log_{0\times 0\times 9}\left(x-1\right)$$

ຄູນ 0 ກັບ 0 ເພື່ອໃຫ້ໄດ້ 0.

$$\log_{0}\left(x-1\right)<\log_{0\times 9}\left(x-1\right)$$

ຄູນ 0 ກັບ 9 ເພື່ອໃຫ້ໄດ້ 0.

$$\log_{0}\left(x-1\right)<\log_{0}\left(x-1\right)$$

ລົບ \log_{0}\left(x-1\right) ອອກຈາກທັງສອງຂ້າງ.

$$\log_{0}\left(x-1\right)-\log_{0}\left(x-1\right)<0$$

ຮວມ \log_{0}\left(x-1\right) ແລະ -\log_{0}\left(x-1\right) ເພື່ອຮັບ 0.

$$0<0$$

ປຽບທຽບ 0 ກັບ 0.

$$\text{false}$$