ແກ້ ell_{2}:x-3=3y-4/6=1-4z/2

$$\ell _ { 2 } : x - 3 = \frac { 3 y - 4 } { 6 } = \frac { 1 - 4 z } { 2 }$$

ປະເມີນ (complex solution)

$$\frac{ℓ_{2}}{x}-3=\frac{y}{2}-\frac{2}{3}\text{ and }\frac{y}{2}-\frac{2}{3}=\frac{1}{2}-2z$$

ແກ້ສຳລັບ x

$$\left\{\begin{matrix}x=\frac{2ℓ_{2}}{7-4z}\text{, }&ℓ_{2}\neq 0\text{ and }y=\frac{7}{3}-4z\text{ and }z\neq \frac{7}{4}\\x\neq 0\text{, }&y=-\frac{14}{3}\text{ and }ℓ_{2}=0\text{ and }z=\frac{7}{4}\end{matrix}\right,$$

ແກ້ສຳລັບ ℓ_2

$$ℓ_{2}=\frac{x\left(7-4z\right)}{2}$$

$$x\neq 0\text{ and }y=\frac{7}{3}-4z$$