सोडोवचें sqrt{sinx/logx}=y

$$\sqrt { \frac { \sin x } { \log x } } = y$$

y खातीर सोडोवचें (जटील सोल्यूशन)

$$y=\sqrt{\ln(10)}\sqrt{\frac{\sin(x)}{\ln(x)}}$$

$$x\neq 0\text{ and }x\neq 1$$

y खातीर सोडोवचें

$$y=\sqrt{\sin(x)\log_{x}\left(10\right)}$$

$$\exists n_{1}\in \mathrm{Z}\text{ : }\left(x\geq 2\pi n_{1}\text{ and }x\leq 2\pi n_{1}+\pi \right)$$

$$n_{1}>0\text{ and }not(n_{1}<1)\text{ or }\left(x>1\text{ and }x\leq \pi \right)$$