सोडोवचें 1/2x(3-x)+3(x+1)(x-1)-x(x-1)^2+(x-1)^3-1/2(2x-8)

$$\frac { 1 } { 2 } x ( 3 - x ) + 3 ( x + 1 ) ( x - 1 ) - x ( x - 1 ) ^ { 2 } + ( x - 1 ) ^ { 3 } - \frac { 1 } { 2 } ( 2 x - 8 )$$

मूल्यांकन करचें

$$\frac{x\left(3x+5\right)}{2}$$

सोडोवणी पांवडे

3-x न \frac{1}{2}x गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{3}{2}x-\frac{1}{2}x^{2}+3\left(x+1\right)\left(x-1\right)-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

x+1 न 3 गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{3}{2}x-\frac{1}{2}x^{2}+\left(3x+3\right)\left(x-1\right)-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

वितरक गूणधर्माचो वापर करून 3x+3 क x-1 न गुणचें आनी संज्ञां भशेन एकठावणी करची.

$$\frac{3}{2}x-\frac{1}{2}x^{2}+3x^{2}-3-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

\frac{5}{2}x^{2} मेळोवंक -\frac{1}{2}x^{2} आनी 3x^{2} एकठांय करचें.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

बायनोमियल प्रमेयाचो वापर करून \left(a-b\right)^{2}=a^{2}-2ab+b^{2} विस्तारावचें \left(x-1\right)^{2}.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-x\left(x^{2}-2x+1\right)+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

x^{2}-2x+1 न x गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-\left(x^{3}-2x^{2}+x\right)+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

x^{3}-2x^{2}+x चो विरोधी सोदूंक, दरेक सज्ञेचो विरोधी सोदचो.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-x^{3}+2x^{2}-x+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

\frac{9}{2}x^{2} मेळोवंक \frac{5}{2}x^{2} आनी 2x^{2} एकठांय करचें.

$$\frac{3}{2}x+\frac{9}{2}x^{2}-3-x^{3}-x+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

\frac{1}{2}x मेळोवंक \frac{3}{2}x आनी -x एकठांय करचें.

$$\frac{1}{2}x+\frac{9}{2}x^{2}-3-x^{3}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

बायनोमियल प्रमेयाचो वापर करून \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} विस्तारावचें \left(x-1\right)^{3}.

$$\frac{1}{2}x+\frac{9}{2}x^{2}-3-x^{3}+x^{3}-3x^{2}+3x-1-\frac{1}{2}\left(2x-8\right)$$

0 मेळोवंक -x^{3} आनी x^{3} एकठांय करचें.

$$\frac{1}{2}x+\frac{9}{2}x^{2}-3-3x^{2}+3x-1-\frac{1}{2}\left(2x-8\right)$$

\frac{3}{2}x^{2} मेळोवंक \frac{9}{2}x^{2} आनी -3x^{2} एकठांय करचें.

$$\frac{1}{2}x+\frac{3}{2}x^{2}-3+3x-1-\frac{1}{2}\left(2x-8\right)$$

\frac{7}{2}x मेळोवंक \frac{1}{2}x आनी 3x एकठांय करचें.

$$\frac{7}{2}x+\frac{3}{2}x^{2}-3-1-\frac{1}{2}\left(2x-8\right)$$

-4 मेळोवंक -3 आनी 1 वजा करचे.

$$\frac{7}{2}x+\frac{3}{2}x^{2}-4-\frac{1}{2}\left(2x-8\right)$$

2x-8 न -\frac{1}{2} गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{7}{2}x+\frac{3}{2}x^{2}-4-x+4$$

\frac{5}{2}x मेळोवंक \frac{7}{2}x आनी -x एकठांय करचें.

$$\frac{5}{2}x+\frac{3}{2}x^{2}-4+4$$

0 मेळोवंक -4 आनी 4 ची बेरीज करची.

$$\frac{5}{2}x+\frac{3}{2}x^{2}$$

विस्तार करचो

$$\frac{3x^{2}+5x}{2}$$

सोडोवणी पांवडे

3-x न \frac{1}{2}x गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{3}{2}x-\frac{1}{2}x^{2}+3\left(x+1\right)\left(x-1\right)-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

x+1 न 3 गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{3}{2}x-\frac{1}{2}x^{2}+\left(3x+3\right)\left(x-1\right)-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

वितरक गूणधर्माचो वापर करून 3x+3 क x-1 न गुणचें आनी संज्ञां भशेन एकठावणी करची.

$$\frac{3}{2}x-\frac{1}{2}x^{2}+3x^{2}-3-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

\frac{5}{2}x^{2} मेळोवंक -\frac{1}{2}x^{2} आनी 3x^{2} एकठांय करचें.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-x\left(x-1\right)^{2}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

बायनोमियल प्रमेयाचो वापर करून \left(a-b\right)^{2}=a^{2}-2ab+b^{2} विस्तारावचें \left(x-1\right)^{2}.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-x\left(x^{2}-2x+1\right)+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

x^{2}-2x+1 न x गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-\left(x^{3}-2x^{2}+x\right)+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

x^{3}-2x^{2}+x चो विरोधी सोदूंक, दरेक सज्ञेचो विरोधी सोदचो.

$$\frac{3}{2}x+\frac{5}{2}x^{2}-3-x^{3}+2x^{2}-x+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

\frac{9}{2}x^{2} मेळोवंक \frac{5}{2}x^{2} आनी 2x^{2} एकठांय करचें.

$$\frac{3}{2}x+\frac{9}{2}x^{2}-3-x^{3}-x+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

\frac{1}{2}x मेळोवंक \frac{3}{2}x आनी -x एकठांय करचें.

$$\frac{1}{2}x+\frac{9}{2}x^{2}-3-x^{3}+\left(x-1\right)^{3}-\frac{1}{2}\left(2x-8\right)$$

बायनोमियल प्रमेयाचो वापर करून \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} विस्तारावचें \left(x-1\right)^{3}.

$$\frac{1}{2}x+\frac{9}{2}x^{2}-3-x^{3}+x^{3}-3x^{2}+3x-1-\frac{1}{2}\left(2x-8\right)$$

0 मेळोवंक -x^{3} आनी x^{3} एकठांय करचें.

$$\frac{1}{2}x+\frac{9}{2}x^{2}-3-3x^{2}+3x-1-\frac{1}{2}\left(2x-8\right)$$

\frac{3}{2}x^{2} मेळोवंक \frac{9}{2}x^{2} आनी -3x^{2} एकठांय करचें.

$$\frac{1}{2}x+\frac{3}{2}x^{2}-3+3x-1-\frac{1}{2}\left(2x-8\right)$$

\frac{7}{2}x मेळोवंक \frac{1}{2}x आनी 3x एकठांय करचें.

$$\frac{7}{2}x+\frac{3}{2}x^{2}-3-1-\frac{1}{2}\left(2x-8\right)$$

-4 मेळोवंक -3 आनी 1 वजा करचे.

$$\frac{7}{2}x+\frac{3}{2}x^{2}-4-\frac{1}{2}\left(2x-8\right)$$

2x-8 न -\frac{1}{2} गुणपाक विभाजक विशमाचो वापर करचो.

$$\frac{7}{2}x+\frac{3}{2}x^{2}-4-x+4$$

\frac{5}{2}x मेळोवंक \frac{7}{2}x आनी -x एकठांय करचें.

$$\frac{5}{2}x+\frac{3}{2}x^{2}-4+4$$

0 मेळोवंक -4 आनी 4 ची बेरीज करची.

$$\frac{5}{2}x+\frac{3}{2}x^{2}$$