{l}{cos(A)=0.5}{a={(sqrt{2})}}{b=a}{text{Solvefor}ctext{where}}{c=b} ಪರಿಹರಿಸಿ

$$\left. \begin{array} { l } { \cos(A) = 0.5 }\\ { a = {(\sqrt{2})} }\\ { b = a }\\ { \text{Solve for } c \text{ where} } \\ { c = b } \end{array} \right.$$

A, a, b, c ಪರಿಹರಿಸಿ (ಸಂಕೀರ್ಣ ಪರಿಹಾರ)

$$A=2\pi n_{1}+\frac{5\pi }{3}\text{, }n_{1}\in \mathrm{Z}\text{, }a=\sqrt{2}\approx 1.414213562\text{, }b=\sqrt{2}\approx 1.414213562\text{, }c=\sqrt{2}\approx 1.414213562$$

$$A=2\pi n_{2}+\frac{\pi }{3}\text{, }n_{2}\in \mathrm{Z}\text{, }a=\sqrt{2}\approx 1.414213562\text{, }b=\sqrt{2}\approx 1.414213562\text{, }c=\sqrt{2}\approx 1.414213562$$

A, a, b, c ಪರಿಹರಿಸಿ

$$A=2\pi n_{1}+\frac{\pi }{3}\text{, }n_{1}\in \mathrm{Z}\text{, }a=\sqrt{2}\approx 1.414213562\text{, }b=\sqrt{2}\approx 1.414213562\text{, }c=\sqrt{2}\approx 1.414213562$$

$$A=2\pi n_{2}+\frac{5\pi }{3}\text{, }n_{2}\in \mathrm{Z}\text{, }a=\sqrt{2}\approx 1.414213562\text{, }b=\sqrt{2}\approx 1.414213562\text{, }c=\sqrt{2}\approx 1.414213562$$