{l}{x/1=y-4/-1=z+1/3}{x-y+3z+8=0} ಪರಿಹರಿಸಿ

$$\left\{ \begin{array} { l } { \frac { x } { 1 } = \frac { y - 4 } { - 1 } = \frac { z + 1 } { 3 } } \\ { x - y + 3 z + 8 = 0 } \end{array} \right.$$

ಮೌಲ್ಯಮಾಪನ (ಸಂಕೀರ್ಣ ಪರಿಹಾರ)

$$x=4-y\text{ and }4-y=\frac{z+1}{3},\ x-y+3z+8=0$$

x ಪರಿಹರಿಸಿ

$$x=-\frac{1}{11}\approx -0.090909091$$

$$z=-\frac{14}{11}\text{ and }y=\frac{45}{11}$$

z ಪರಿಹರಿಸಿ

$$z = -\frac{14}{11} = -1\frac{3}{11} = -1.2727272727272727$$

$$x=-\frac{1}{11}\text{ and }y=\frac{45}{11}$$