ដោះស្រាយ d=0,43/tanθ

$$d = \frac { 0,43 } { \tan \theta }$$

ដោះស្រាយសម្រាប់ d

$$d=\frac{43\cot(\theta )}{100}$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =\frac{\pi n_{1}}{2}$$

ដោះស្រាយសម្រាប់ θ

$$\theta =2\pi n_{14}+\left(-1\right)\pi +ArcCosI(100\left(1849+10000d^{2}\right)^{-\frac{1}{2}}d)\text{, }n_{14}\in \mathrm{Z}\text{, }\exists n_{175}\in \mathrm{Z}\text{ : }\left(n_{14}>\left(-\frac{1}{2}\right)\left(\left(-1\right)\pi +ArcCosI(100\left(1849+10000d^{2}\right)^{-\frac{1}{2}}d)+\left(-\frac{1}{2}\right)\pi n_{175}\right)\pi ^{-1}\text{ and }2\pi n_{14}+\left(-1\right)\pi +ArcCosI(100\left(1849+10000d^{2}\right)^{-\frac{1}{2}}d)<\frac{1}{2}\pi \left(n_{175}+1\right)\right)\text{ and }\nexists n_{5}\in \mathrm{Z}\text{ : }2\pi n_{14}+\left(-1\right)\pi +ArcCosI(100\left(1849+10000d^{2}\right)^{-\frac{1}{2}}d)=\frac{1}{2}\pi n_{5}$$

$$\theta =ArcCosI(100\left(1849+10000d^{2}\right)^{-\frac{1}{2}}d)+2\pi n_{149}\text{, }n_{149}\in \mathrm{Z}\text{, }\nexists n_{5}\in \mathrm{Z}\text{ : }ArcCosI(100\left(1849+10000d^{2}\right)^{-\frac{1}{2}}d)+2\pi n_{149}=\frac{1}{2}\pi n_{5}\text{ and }\nexists n_{5}\in \mathrm{Z}\text{ : }ArcCosI(100\left(1849+10000d^{2}\right)^{-\frac{1}{2}}d)+2\pi n_{149}=\frac{1}{2}\pi n_{5}$$