ដោះស្រាយ a^{2}c^{2}-b^2c^2=a^4-b^4i

$$a ^ { 2 } c ^ { 2 } - b ^ { 2 } c ^ { 2 } = a ^ { 4 } - b ^ { 4 } i$$

ដោះស្រាយសម្រាប់ a

$$a=\frac{\sqrt{2\left(\sqrt{4ib^{4}+c^{4}-4\left(bc\right)^{2}}+c^{2}\right)}}{2}$$

$$a=-\frac{\sqrt{2\left(\sqrt{4ib^{4}+c^{4}-4\left(bc\right)^{2}}+c^{2}\right)}}{2}$$

$$a=-\frac{\sqrt{2\left(-\sqrt{4ib^{4}+c^{4}-4\left(bc\right)^{2}}+c^{2}\right)}}{2}$$

$$a=\frac{\sqrt{2\left(-\sqrt{4ib^{4}+c^{4}-4\left(bc\right)^{2}}+c^{2}\right)}}{2}$$

ដោះស្រាយសម្រាប់ b

$$b=\frac{\sqrt{2i\sqrt{4ia^{4}+c^{4}-4i\left(ac\right)^{2}}-2ic^{2}}}{2}$$

$$b=-\frac{\sqrt{2i\sqrt{4ia^{4}+c^{4}-4i\left(ac\right)^{2}}-2ic^{2}}}{2}$$

$$b=-\frac{\sqrt{-2i\sqrt{4ia^{4}+c^{4}-4i\left(ac\right)^{2}}-2ic^{2}}}{2}$$

$$b=\frac{\sqrt{-2i\sqrt{4ia^{4}+c^{4}-4i\left(ac\right)^{2}}-2ic^{2}}}{2}$$