ដោះស្រាយ 12=3/2pmsqrt{(-3/2)^2-4*frac{1/4*225}}{2*1/4}=frac{frac{3}{2}}{frac{1}{3}}

$$12 = \frac { \frac { 3 } { 2 } \pm \sqrt { ( - \frac { 3 } { 2 } ) ^ { 2 } - 4 \cdot \frac { 1 } { 4 } \cdot 225 } } { 2 \cdot \frac { 1 } { 4 } } = \frac { \frac { 3 } { 2 } } { \frac { 1 } { 3 } }$$

វាយតម្លៃ (complex solution)

$$12=2\left(\frac{3}{2}±\frac{9\sqrt{11}i}{2}\right)\text{ and }2\left(\frac{3}{2}±\frac{9\sqrt{11}i}{2}\right)=\frac{9}{2}$$

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