ដោះស្រាយ 9^81*168/17+48^2

$${ 9 }^{ 81 } \times \frac{ 168 }{ 17 } + { 48 }^{ 2 }$$

វាយតម្លៃ

$$\frac{33033344479892889487836752632521235535561379758628080843788989810378353721103080}{17}\approx 1.943137911 \cdot 10^{78}$$

ជំហានចម្លើយ

គណនាស្វ័យគុណ 9 នៃ 81 ហើយបាន 196627050475552913618075908526912116283103450944214766927315415537966391196809។

$$196627050475552913618075908526912116283103450944214766927315415537966391196809\times \frac{168}{17}+48^{2}$$

បង្ហាញ 196627050475552913618075908526912116283103450944214766927315415537966391196809\times \frac{168}{17} ជាប្រភាគទោល។

$$\frac{196627050475552913618075908526912116283103450944214766927315415537966391196809\times 168}{17}+48^{2}$$

គុណ 196627050475552913618075908526912116283103450944214766927315415537966391196809 និង 168 ដើម្បីបាន 33033344479892889487836752632521235535561379758628080843788989810378353721063912។

$$\frac{33033344479892889487836752632521235535561379758628080843788989810378353721063912}{17}+48^{2}$$

គណនាស្វ័យគុណ 48 នៃ 2 ហើយបាន 2304។

$$\frac{33033344479892889487836752632521235535561379758628080843788989810378353721063912}{17}+2304$$

បម្លែង 2304 ទៅជាប្រភាគ \frac{39168}{17}។

$$\frac{33033344479892889487836752632521235535561379758628080843788989810378353721063912}{17}+\frac{39168}{17}$$

ដោយសារ \frac{33033344479892889487836752632521235535561379758628080843788989810378353721063912}{17} និង \frac{39168}{17} មានភាគបែងដូចគ្នា សូមបូកពួកវាដោយការបូកភាគយករបស់ពួកវា។

$$\frac{33033344479892889487836752632521235535561379758628080843788989810378353721063912+39168}{17}$$

បូក 33033344479892889487836752632521235535561379758628080843788989810378353721063912 និង 39168 ដើម្បីបាន 33033344479892889487836752632521235535561379758628080843788989810378353721103080។

$$\frac{33033344479892889487836752632521235535561379758628080843788989810378353721103080}{17}$$