ដោះស្រាយ {l}{x^2=42}{y=x+pi}{z=y}{a=z}{text{Solvefor}btext{where}}{b=a}

$$\left. \begin{array} { l } { x ^ {2} = 42 }\\ { y = x + \pi }\\ { z = y }\\ { a = z }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.$$

ដោះស្រាយសម្រាប់ x, y, z, a, b

$$x=-\sqrt{42}\approx -6.480740698\text{, }y=\pi -\sqrt{42}\approx -3.339148045\text{, }z=\pi -\sqrt{42}\approx -3.339148045\text{, }a=\pi -\sqrt{42}\approx -3.339148045\text{, }b=\pi -\sqrt{42}\approx -3.339148045$$

$$x=\sqrt{42}\approx 6.480740698\text{, }y=\pi +\sqrt{42}\approx 9.622333352\text{, }z=\pi +\sqrt{42}\approx 9.622333352\text{, }a=\pi +\sqrt{42}\approx 9.622333352\text{, }b=\pi +\sqrt{42}\approx 9.622333352$$