y16x+10yleq16000 шешу

$$y 16 x + 10 y \leq 16000$$

x теңдеуін шешу

$$\left\{\begin{matrix}x\in \begin{bmatrix}\text{Indeterminate},-\frac{10\left(y-1600\right)}{y_{16}}\end{bmatrix}\text{, }&y_{16}>0\text{ and }\text{Indeterminate}\leq 0\\x\leq -\frac{10\left(y-1600\right)}{y_{16}}\text{, }&y_{16}>0\\x\in \mathrm{R}\text{, }&y\leq 1600\text{ and }y_{16}=0\\x=-\frac{10\left(y-1600\right)}{y_{16}}\text{, }&y\leq 1600\text{ or }y_{16}\neq 0\\x\geq -\frac{10\left(y-1600\right)}{y_{16}}\text{, }&y_{16}<0\\x\geq \text{Indeterminate}\text{, }&\left(\text{Indeterminate}>-\frac{10y-16000}{y_{16}}\text{ and }y_{16}<0\right)\text{ or }\left(y\leq 1600\text{ and }y_{16}\leq 0\right)\end{matrix}\right.$$

y_16 теңдеуін шешу

$$\left\{\begin{matrix}y_{16}\in \begin{bmatrix}\text{Indeterminate},-\frac{10\left(y-1600\right)}{x}\end{bmatrix}\text{, }&x>0\text{ and }\text{Indeterminate}\leq 0\\y_{16}\leq -\frac{10\left(y-1600\right)}{x}\text{, }&x>0\\y_{16}\in \mathrm{R}\text{, }&y\leq 1600\text{ and }x=0\\y_{16}=-\frac{10\left(y-1600\right)}{x}\text{, }&y\leq 1600\text{ or }x\neq 0\\y_{16}\geq -\frac{10\left(y-1600\right)}{x}\text{, }&x<0\\y_{16}\geq \text{Indeterminate}\text{, }&\left(\text{Indeterminate}>-\frac{10y-16000}{x}\text{ and }x<0\right)\text{ or }\left(y\leq 1600\text{ and }x\leq 0\right)\end{matrix}\right.$$