y=-2tanx шешу

$$y = - 2 \tan x$$

x мәнін табыңыз

$$x=2\pi n_{1}-\arcsin(\frac{y}{\sqrt{y^{2}+4}})+\pi \text{, }n_{1}\in \mathrm{Z}\text{, }\exists n_{3}\in \mathrm{Z}\text{ : }\left(n_{1}>\frac{2n_{3}+\frac{2\arcsin(\frac{y}{\sqrt{y^{2}+4}})}{\pi }-1}{4}\text{ and }n_{1}<\frac{2n_{3}+\frac{2\arcsin(\frac{y}{\sqrt{y^{2}+4}})}{\pi }+1}{4}\right)$$

$$x=2\pi n_{2}-\arcsin(\frac{y}{\sqrt{y^{2}+4}})\text{, }n_{2}\in \mathrm{Z}\text{, }\exists n_{3}\in \mathrm{Z}\text{ : }\left(n_{3}>\frac{4n_{2}-\frac{2\arcsin(\frac{y}{\sqrt{y^{2}+4}})}{\pi }-3}{2}\text{ and }n_{3}<\frac{4n_{2}-\frac{2\arcsin(\frac{y}{\sqrt{y^{2}+4}})}{\pi }-1}{2}\right)$$

y мәнін табыңыз

$$y=-2\tan(x)$$

$$\nexists n_{1}\in \mathrm{Z}\text{ : }x=\pi n_{1}+\frac{\pi }{2}$$