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2 \times 3 \times 7

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次に類似した 5 個の問題:

f a c t o r (42)

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f a c t o r 9.12

https://www.tiger-algebra.com/drill/factor9.12/

(912/100) Final result : 228 ——— = 9.12000 25 Reformatting the input : Changes made to your input should not affect the solution: (1): "9.12" was replaced by "(912/100)". Step by step solution : ...

g 2 - 11 g + 30 = 0

https://www.tiger-algebra.com/drill/g2-11g_30=0/

g2-11g+30=0 Two solutions were found : g = 6 g = 5 Reformatting the input : Changes made to your input should not affect the solution: (1): "g2" was replaced by "g^2". Step by step ...

Why does mathematical convention deal so ineptly with multisets?

https://math.stackexchange.com/q/152223/11994

This question reminded me of several notes by the influential computer scientist Edsger W. Dijkstra, who spent a lot of time thinking about how our notation can affect how we think and reason ...

Cayley-Hamilton Theorem proof

https://math.stackexchange.com/questions/3104993/cayley-hamilton-theorem-proof

You are trying to show that:

(P^{- 1} A P - λ_{1} I)^{k_{1}} \dots (P^{- 1} A P - λ_{m} I)^{k_{m}} = 0

let's take one subspace:

(P^{- 1} A P - λ_{1} I)^{k_{1}}

then it's equal to \begin{bmatrix} ...

Cannot find length of repeating block in decimal expansion for

\frac{1 7}{7 8}

https://math.stackexchange.com/questions/802448/cannot-find-length-of-repeating-block-in-decimal-expansion-for-frac1778

Note that the period for a prime

p

φ (p) = p - 1

but need not be equal to it. This is because

1 0^{p - 1} \equiv 1 m o d p

. The period is the least

n

p ∣ (1 0^{n} - 1)

Is it a valid algorithm to win at the casino roulette?

https://stats.stackexchange.com/q/100137

You have discovered the Martingale . It is a perfectly reasonable betting strategy, which was played by Casanova and also by Charles Wells , but unfortunately it doesn't win in the long run. ...

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