2m^2+5m=2n^2+5n=14 を解きます| Microsoft 数学ソルバー

$$2 m ^ { 2 } + 5 m = 2 n ^ { 2 } + 5 n = 14$$

計算 (複素数の解)

$$m\left(2m+5\right)=n\left(2n+5\right)\text{ and }\left(n=\frac{\sqrt{137}-5}{4}\text{ or }n=\frac{-\sqrt{137}-5}{4}\right)$$

n を解く

$$n = \frac{-\sqrt{137} - 5}{4} = -4.176174977679906$$

$$n=\frac{\sqrt{137}-5}{4}\text{, }m=\frac{\sqrt{137}-5}{4}\text{ or }m=\frac{-\sqrt{137}-5}{4}$$

m を解く

$$m = \frac{\sqrt{137} - 5}{4} = 1.6761749776799064$$

$$m=\frac{-\sqrt{137}-5}{4}\text{, }n=\frac{\sqrt{137}-5}{4}\text{ or }n=\frac{-\sqrt{137}-5}{4}$$