{l}{(nN+1)lambda_{1}=Nnlambda_{2}}{(nN+1)lambda_{1}=N_{N}(1)} を解きます| Microsoft 数学ソルバー

$$\left. \begin{array} { l } { ( n N + 1 ) \lambda _ { 1 } = N n \lambda _ { 2 } } \\ { ( n N + 1 ) \lambda _ { 1 } = N _ { N } ( 1 ) } \end{array} \right.$$

n,N,λ_1,λ_2,N_N を解く

$$n=-\frac{\lambda _{1}}{N\left(\lambda _{1}-\lambda _{2}\right)}\text{, }N\neq 0\text{, }\lambda _{1}\neq \lambda _{2}\text{, }\lambda _{2}\in \mathrm{R}\text{, }N_{N}=\frac{\lambda _{1}\lambda _{2}}{\lambda _{2}-\lambda _{1}}$$

$$n\in \mathrm{R}\text{, }N=0\text{, }\lambda _{1}=0\text{, }\lambda _{2}\in \mathrm{R}\text{, }N_{N}=0$$

$$n\in \mathrm{R}\text{, }N\in \mathrm{R}\text{, }\lambda _{1}=0\text{, }\lambda _{2}=0\text{, }N_{N}=0$$