∫ xsqrt{2x++1 wrt x を解きます| Microsoft 数学ソルバー

計算

\frac{( 2 x + 1 ) ^{\frac{5}{2}}}{1 0} - \frac{( 2 x + 1 ) ^{\frac{3}{2}}}{6} + С

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x で微分する

2 x + 1 x

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次に類似した 5 個の問題:

\int x 2 x + + 1 d x

Web 検索からの類似の問題

How do you integrate

\int x 2 x + 1 d x

https://socratic.org/questions/how-do-you-integrate-int-xsqrt-2x-1-dx

\frac{1}{1 5} (2 x + 1)^{\frac{3}{2}} (3 x - 1) + C .

Explanation: Let

2 x + 1 = t^{2} ∴ x = \frac{t ^{2} - 1}{2}, and, d x = t d t .

How do you integrate

\int x 3 x + 1 d x

https://socratic.org/questions/58f240b27c0149728333512c

\int x 3 x + 1 = \frac{2}{9} x (3 x + 1)^{\frac{3}{2}} - \frac{4}{1 3 5} (3 x + 1)^{\frac{5}{2}} + C

Explanation: You will ...

How to integrate

\int 12 x [x + 1] d x

using integration by parts ?

https://socratic.org/questions/how-to-integrate-int12x-sqrt-x-1-dx-using-integration-by-parts

= 8 x (1 + x)^{\frac{3}{2}} - \frac{1 6}{5} (1 + x)^{\frac{5}{2}} + C

Explanation: We need We solve this integral by ...

An easier way to find the integral of:

\int x 2 + x d x

u^{2} = 2 + x

https://math.stackexchange.com/questions/386161/an-easier-way-to-find-the-integral-of-int-x-sqrt-2-x-rm-dx-wher/386404

Let's use your substitution, without the unnecessary manipulations. Let

u^{2} = x + 2

2 u d u = d x

x = u^{2} - 2

. Substitute, getting rid of all

x

all at once. We get

\int (u^{2} - 2) (u) (2 u) d u = \int (2 u^{4} - 4 u^{2}) d u = \frac{2 u ^{5}}{5} - \frac{4 u ^{3}}{3} + C .

How do you integrate

\int (x - 1) 2 - x d x

https://socratic.org/questions/how-do-you-integrate-int-x-1-sqrt-2-x-dx-from-1-2

-4/15 Explanation: u substitution: u = 2-x du = -dx x - 1 = 1 - u,

\int_{1}^{2} (x - 1) 2 - x d x = - \int_{1}^{0} (1 - u) u d u = - \int_{1}^{0} u - u u d u = - \int_{1}^{0} u^{\frac{1}{2}} - u^{\frac{3}{2}} d u = \int_{0}^{1} u^{\frac{1}{2}} - u^{\frac{3}{2}} d u

How do you evaluate the integral

\int 2 x + 3 d x

https://socratic.org/questions/how-do-you-evaluate-the-integral-int-sqrt-2x-3

= \frac{1}{3} (2 x + 3)^{\frac{3}{2}} + C

Explanation: Let

u = 2 x + 3

d u = 2 d x

d x = \frac{1}{2} d u

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例

二次方程式の公式

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

一次方程式

y = 3 x + 4

699 * 533

マトリックス

[2534] [2 - 1 0135]

連立方程式

{8 x + 2 y = 46 7 x + 3 y = 47

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}