(x-1)^2/5^2-(y-2)^2/2^2=1 を解きます| Microsoft 数学ソルバー

$$\frac { ( x - 1 ) ^ { 2 } } { 5 ^ { 2 } } - \frac { ( y - 2 ) ^ { 2 } } { 2 ^ { 2 } } = 1$$

y を解く (複素数の解)

$$y=-\frac{2\sqrt{x-6}\sqrt{x+4}}{5}+2$$

$$y=\frac{2\sqrt{x-6}\sqrt{x+4}}{5}+2$$

x を解く

$$x=\frac{5\sqrt{y^{2}-4y+8}}{2}+1$$

$$x=-\frac{5\sqrt{y^{2}-4y+8}}{2}+1$$

y を解く

$$\left\{\begin{matrix}y=\frac{2\left(-\sqrt{\left(x-6\right)\left(x+4\right)}+5\right)}{5}\text{; }y=\frac{2\left(\sqrt{\left(x-6\right)\left(x+4\right)}+5\right)}{5}\text{, }&x\geq 6\\y=\frac{2\left(-\sqrt{\left(x-6\right)\left(x+4\right)}+5\right)}{5}\text{; }y=\frac{2\left(\sqrt{\left(x-6\right)\left(x+4\right)}+5\right)}{5}\text{, }&x\leq -4\end{matrix}\right.$$