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Fattore
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Calcola
\frac{415}{32}=12.96875
3
2
4
1
5
=
1
2
.
9
6
8
7
5
Scomponi in fattori
\frac{5 \cdot 83}{2 ^ {5}} = 12\frac{31}{32} = 12.96875
2
5
5
⋅
8
3
=
1
2
3
2
3
1
=
1
2
.
9
6
8
7
5
Quiz
Arithmetic
5 problemi simili a:
415/32
4
1
5
/
3
2
Problemi simili da ricerca Web
15/300
1
5
/
3
0
0
https://www.tiger-algebra.com/drill/15/300/
15/300 Final result : 1 —— = 0.05000 20 Step by step solution : Step 1 : 1 Simplify —— 20 Final result : 1 —— = 0.05000 20 Processing ends successfully
15/300 Final result : 1 —— = 0.05000 20 Step by step solution : Step 1 : 1 Simplify —— 20 Final result : 1 —— = 0.05000 20 Processing ends successfully
Describe 15/(4,3,2,1) as a vector
Describe
1
5
/
(
4
,
3
,
2
,
1
)
as a vector
https://math.stackexchange.com/questions/1902548/describe-15-4-3-2-1-as-a-vector
It looks as if this non-standard notation is asking to find the vector x of the smallest Euclidean norm so that x\cdot (4,3,2,1) = 15. This is the same as making an orthogonal projection (do you ...
It looks as if this non-standard notation is asking to find the vector
x
of the smallest Euclidean norm so that
x
⋅
(
4
,
3
,
2
,
1
)
=
1
5
. This is the same as making an orthogonal projection (do you ...
What are the mean and standard deviation of a binomial probability distribution with \displaystyle{n}={4} and \displaystyle{p}=\frac{{15}}{{32}} ?
What are the mean and standard deviation of a binomial probability distribution with
n
=
4
and
p
=
3
2
1
5
?
https://socratic.org/questions/what-are-the-mean-and-standard-deviation-of-a-binomial-probability-distribution--62
Mean \displaystyle={1}\frac{{7}}{{8}} SD \displaystyle={0.998} Explanation: Given- \displaystyle{n}={4} \displaystyle{p}=\frac{{15}}{{32}} \displaystyle{q}={1}-{p}={1}-\frac{{15}}{{32}}=\frac{{17}}{{32}} ...
Mean
=
1
8
7
SD
=
0
.
9
9
8
Explanation: Given-
n
=
4
p
=
3
2
1
5
q
=
1
−
p
=
1
−
3
2
1
5
=
3
2
1
7
...
105/30
1
0
5
/
3
0
https://www.tiger-algebra.com/drill/105/30/
105/30 Final result : 7 — = 3.50000 2 Step by step solution : Step 1 : 7 Simplify — 2 Final result : 7 — = 3.50000 2 Processing ends successfully
105/30 Final result : 7 — = 3.50000 2 Step by step solution : Step 1 : 7 Simplify — 2 Final result : 7 — = 3.50000 2 Processing ends successfully
115/35
1
1
5
/
3
5
http://www.tiger-algebra.com/drill/115/35/
115/35 Final result : 23 —— = 3.28571 7 Step by step solution : Step 1 : 23 Simplify —— 7 Final result : 23 —— = 3.28571 7 Processing ends successfully
115/35 Final result : 23 —— = 3.28571 7 Step by step solution : Step 1 : 23 Simplify —— 7 Final result : 23 —— = 3.28571 7 Processing ends successfully
If acceleration is increasing at the constant rate of \displaystyle{2}\frac{{m}}{{s}^{{2}}} . Find the distance travelled in \displaystyle{5}{\sec} ? If initial velocity and acceleration both ...
If acceleration is increasing at the constant rate of
2
s
2
m
. Find the distance travelled in
5
sec
? If initial velocity and acceleration both ...
https://socratic.org/questions/if-acceleration-is-increasing-at-the-constant-rate-of-2-m-s-2-find-the-distance-
After 5 seconds the object will have reached a speed of: \displaystyle{v}={5}{s}\times{2}{m}{/}{s}^{{2}}={10}{m}{/}{s} Explanation: Since the speed goes up from 0 to 10 m/s at a constant rate, ...
After 5 seconds the object will have reached a speed of:
v
=
5
s
×
2
m
/
s
2
=
1
0
m
/
s
Explanation: Since the speed goes up from 0 to 10 m/s at a constant rate, ...
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Problemi analoghi
3 \frac{ 3 }{ 7 }
3
7
3
4 \frac{ 15 }{ 32 }
4
3
2
1
5
1 \frac{ 1 }{ 2 } +3 \frac{ 4 }{ 5 }
1
2
1
+
3
5
4
1 \frac{ 1 }{ 2 } -3 \frac{ 4 }{ 5 }
1
2
1
−
3
5
4
1 \frac{ 1 }{ 2 } \times 3 \frac{ 4 }{ 5 }
1
2
1
×
3
5
4
1 \frac{ 1 }{ 2 } \div 3 \frac{ 4 }{ 5 }
1
2
1
÷
3
5
4
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