Risolvi E=frac{80^{x-3}+6^x+1+24^x-2}{44^x-1-2^x+2}

$$E = \frac { 80 ^ { x - 3 } + 6 ^ { x + 1 } + 24 ^ { x - 2 } } { 44 ^ { x - 1 } - 2 ^ { x + 2 } }$$

Trova E (soluzione complessa)

$$\left\{\begin{matrix}E=\frac{11\left(9\times 80^{x}+8000\times 24^{x}[phone]\times 6^{x}\right)}{1152000\left(44^{x}-176\times 2^{x}\right)}\text{, }&1152000\times 44^{x}-202752000\times 2^{x}\neq 0\text{ and }44^{x}-176\times 2^{x}\neq 0\text{ and }44^{x-1}-2^{x+2}\neq 0\\E\in \mathrm{C}\text{, }&-99\times 80^{x}-88000\times 24^{x}-304128000\times 6^{x}=0\text{ and }1152000\times 44^{x}-202752000\times 2^{x}=0\text{ and }44^{x}-176\times 2^{x}\neq 0\text{ and }44^{x-1}-2^{x+2}\neq 0\end{matrix}\right,$$

Trova E

$$E=\frac{11\left(9\times 40^{x}+8000\times 12^{x}[phone]\times 3^{x}\right)}{1152000\left(22^{x}-176\right)}$$

$$x\neq \log_{22}\left(176\right)$$