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Minimo comune multiplo
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Frazioni
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Esponenti
Radicali
Algebra
Combinazione di termini simili
Risolvere una variabile
Fattore
Espandi
Calcolo delle frazioni
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Equazioni di secondo grado
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Elenco
Trova θ
\theta =2\pi n_{1}+\frac{2\pi }{3}\text{, }n_{1}\in \mathrm{Z}<br/>\theta =2\pi n_{1}+\frac{4\pi }{3}\text{, }n_{1}\in \mathrm{Z}
θ
=
2
π
n
1
+
3
2
π
,
n
1
∈
Z
θ
=
2
π
n
1
+
3
4
π
,
n
1
∈
Z
Grafico
Quiz
Trigonometry
5 problemi simili a:
2 \cos ^ { 2 } \theta + 9 \cos \theta + 4 = 0
2
cos
2
θ
+
9
cos
θ
+
4
=
0
Problemi simili da ricerca Web
How do you find the solution to \displaystyle{6}{{\cos}^{{2}}\theta}+{5}{\cos{\theta}}-{4}={0} if \displaystyle{0}\le\theta{<}{360} ?
How do you find the solution to
6
cos
2
θ
+
5
cos
θ
−
4
=
0
if
0
≤
θ
<
3
6
0
?
https://socratic.org/questions/how-do-you-find-the-solution-to-6cos-2theta-5costheta-4-0-if-0-theta-360
The solutions are \displaystyle{S}={\left\lbrace{60}^{\circ},{300}^{\circ}\right\rbrace} for \displaystyle\theta\in{\left[{0},{360}\right)} Explanation: This is a quadratic equation in \displaystyle{\cos{\theta}} ...
The solutions are
S
=
{
6
0
∘
,
3
0
0
∘
}
for
θ
∈
[
0
,
3
6
0
)
Explanation: This is a quadratic equation in
cos
θ
...
How do you solve the equation \displaystyle{2}{{\cos}^{{2}}\theta}-{3}{\cos{\theta}}+{1}={0} for \displaystyle{0}\le\theta{<}{2}\pi ?
How do you solve the equation
2
cos
2
θ
−
3
cos
θ
+
1
=
0
for
0
≤
θ
<
2
π
?
https://socratic.org/questions/how-do-you-solve-the-equation-2cos-2theta-3costheta-1-0-for-0-theta-2pi
The solutions are \displaystyle{S}={\left\lbrace{0},\frac{\pi}{{3}},\frac{{{5}\pi}}{{3}}\right\rbrace} Explanation: Let's factorise the LHS \displaystyle{2}{{\cos}^{{2}}\theta}-{3}{\cos{\theta}}+{1}={\left({2}{\cos{\theta}}-{1}\right)}{\left({\cos{\theta}}-{1}\right)}={0} ...
The solutions are
S
=
{
0
,
3
π
,
3
5
π
}
Explanation: Let's factorise the LHS
2
cos
2
θ
−
3
cos
θ
+
1
=
(
2
cos
θ
−
1
)
(
cos
θ
−
1
)
=
0
...
How do you solve \displaystyle{2}{{\cos}^{{2}}\theta}+{\cos{\theta}}-{1}={0} ?
How do you solve
2
cos
2
θ
+
cos
θ
−
1
=
0
?
https://socratic.org/questions/how-do-you-solve-2cos-2-theta-cos-theta-1-0-1
\displaystyle{\left({1}+{2}{k}\right)}\pi;\frac{\pi}{{3}}+{2}{k}\pi;\frac{{{5}\pi}}{{3}}+{2}{k}\pi Explanation: Solve the quadratic equation for cos t. \displaystyle{f{{\left({t}\right)}}}={2}{{\cos}^{{2}}{t}}+{\cos{{t}}}-{1}={0} ...
(
1
+
2
k
)
π
;
3
π
+
2
k
π
;
3
5
π
+
2
k
π
Explanation: Solve the quadratic equation for cos t.
f
(
t
)
=
2
cos
2
t
+
cos
t
−
1
=
0
...
How do you solve \displaystyle{2}{{\cos}^{{2}}\theta}-{4}{\cos{\theta}}-{5}={0} in the interval \displaystyle{0}\le{x}\le{2}\pi ?
How do you solve
2
cos
2
θ
−
4
cos
θ
−
5
=
0
in the interval
0
≤
x
≤
2
π
?
https://socratic.org/questions/how-do-you-solve-2cos-2theta-4costheta-5-0-in-the-interval-0-x-2pi
\displaystyle\theta={150.56} deg Explanation: \displaystyle{2}{{\cos}^{{2}}\theta}-{4}{\cos{\theta}}-{5}={0} . Note that this equation looks like the quadratic equation \displaystyle{2}{x}^{{2}}-{4}{x}-{5}={0} ...
θ
=
1
5
0
.
5
6
deg Explanation:
2
cos
2
θ
−
4
cos
θ
−
5
=
0
. Note that this equation looks like the quadratic equation
2
x
2
−
4
x
−
5
=
0
...
The tangent and the normal to the conic \displaystyle\frac{{x}^{{2}}}{{a}^{{2}}}+\frac{{y}^{{2}}}{{b}^{{2}}}={1} at a point \displaystyle{\left({a}{\cos{\theta}},{b}{\sin{\theta}}\right)} meet ...
The tangent and the normal to the conic
a
2
x
2
+
b
2
y
2
=
1
at a point
(
a
cos
θ
,
b
sin
θ
)
meet ...
https://socratic.org/questions/the-tangent-and-the-normal-to-the-conic-x-2-a-2-y-2-b-2-1-at-a-point-acostheta-b
See below. Explanation: At point \displaystyle{x}_{{0}},{y}_{{0}} there is a tangent line and a normal line given by \displaystyle{L}_{{t}}\to{y}={y}_{{0}}+{m}_{{0}}{\left({x}-{x}_{{0}}\right)} ...
See below. Explanation: At point
x
0
,
y
0
there is a tangent line and a normal line given by
L
t
→
y
=
y
0
+
m
0
(
x
−
x
0
)
...
How do you find all solutions of the equation in the interval (0, 2pi) \displaystyle{2}{{\cos}^{{2}}\theta}+{\cos{\theta}}={0} ?
How do you find all solutions of the equation in the interval (0, 2pi)
2
cos
2
θ
+
cos
θ
=
0
?
https://socratic.org/questions/how-do-you-find-all-solutions-of-the-equation-in-the-interval-0-2pi-2cos-2-theta
Factor out a cos. Explanation: \displaystyle{\cos{\theta}}{\left({2}{\cos{\theta}}+{1}\right)}={0} \displaystyle{\cos{\theta}}={0}{\quad\text{or}\quad}{2}{\cos{\theta}}+{1}={0} \displaystyle\theta=\pi,\frac{{{3}\pi}}{{2}}{\quad\text{or}\quad}{\cos{\theta}}=-\frac{{1}}{{2}} ...
Factor out a cos. Explanation:
cos
θ
(
2
cos
θ
+
1
)
=
0
cos
θ
=
0
or
2
cos
θ
+
1
=
0
θ
=
π
,
2
3
π
or
cos
θ
=
−
2
1
...
Altri Elementi
Condividi
Copia
Copiato negli Appunti
Esempi
Equazione quadratica
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometria
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Equazione lineare
y = 3x + 4
y
=
3
x
+
4
Aritmetica
699 * 533
6
9
9
∗
5
3
3
Matrice
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Equazione simultanea
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Differenziazione
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integrazione
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Limiti
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
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