Risolvi 2cos^2θ+9cosθ+4=0 | Microsoft Math Solver

Trova θ

θ = 2 π n_{1} + \frac{2 π}{3}, n_{1} \in Z

θ = 2 π n_{1} + \frac{4 π}{3}, n_{1} \in Z

Tick mark Image

Grafico

Quiz

5 problemi simili a:

2 cos^{2} θ + 9 cos θ + 4 = 0

Problemi simili da ricerca Web

How do you find the solution to

6 cos^{2} θ + 5 cos θ - 4 = 0

0 \leq θ < 360

https://socratic.org/questions/how-do-you-find-the-solution-to-6cos-2theta-5costheta-4-0-if-0-theta-360

The solutions are

S = {60^{\circ}, 300^{\circ}}

θ \in [0, 360)

Explanation: This is a quadratic equation in

cos θ

How do you solve the equation

2 cos^{2} θ - 3 cos θ + 1 = 0

0 \leq θ < 2 π

https://socratic.org/questions/how-do-you-solve-the-equation-2cos-2theta-3costheta-1-0-for-0-theta-2pi

The solutions are

S = {0, \frac{π}{3}, \frac{5 π}{3}}

Explanation: Let's factorise the LHS

2 cos^{2} θ - 3 cos θ + 1 = (2 cos θ - 1) (cos θ - 1) = 0

How do you solve

2 cos^{2} θ + cos θ - 1 = 0

https://socratic.org/questions/how-do-you-solve-2cos-2-theta-cos-theta-1-0-1

(1 + 2 k) π; \frac{π}{3} + 2 k π; \frac{5 π}{3} + 2 k π

Explanation: Solve the quadratic equation for cos t.

f (t) = 2 cos^{2} t + cos t - 1 = 0

How do you solve

2 cos^{2} θ - 4 cos θ - 5 = 0

in the interval

0 \leq x \leq 2 π

https://socratic.org/questions/how-do-you-solve-2cos-2theta-4costheta-5-0-in-the-interval-0-x-2pi

θ = 150.56

deg Explanation:

2 cos^{2} θ - 4 cos θ - 5 = 0

. Note that this equation looks like the quadratic equation

2 x^{2} - 4 x - 5 = 0

The tangent and the normal to the conic

\frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}} = 1

(a cos θ, b sin θ)

https://socratic.org/questions/the-tangent-and-the-normal-to-the-conic-x-2-a-2-y-2-b-2-1-at-a-point-acostheta-b

See below. Explanation: At point

x_{0}, y_{0}

there is a tangent line and a normal line given by

L_{t} \to y = y_{0} + m_{0} (x - x_{0})

How do you find all solutions of the equation in the interval (0, 2pi)

2 cos^{2} θ + cos θ = 0

https://socratic.org/questions/how-do-you-find-all-solutions-of-the-equation-in-the-interval-0-2pi-2cos-2-theta

Factor out a cos. Explanation:

cos θ (2 cos θ + 1) = 0

cos θ = 0 or 2 cos θ + 1 = 0

θ = π, \frac{3 π}{2} or cos θ = - \frac{1}{2}

Condividi

reddit

Copia

Copiato negli Appunti

Esempi

Equazione quadratica

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

Equazione lineare

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

Equazione simultanea

{8 x + 2 y = 46 7 x + 3 y = 47

Differenziazione

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}