Risolvi 2*sqrt[3]{-125}+4*sqrt[5]{32}-6*sqrt[3]{-8} | Microsoft Math Solver

Calcola

10

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Procedura della soluzione

2 \cdot 3 - 125 + 4 \cdot 532 - 6 \cdot 3 - 8

Calcola

3 - 125

e ottieni

- 5

.

2 (- 5) + 4532 - 6 3 - 8

Moltiplica

2

e

- 5

per ottenere

- 10

.

- 10 + 4532 - 6 3 - 8

Calcola

532

e ottieni

2

.

- 10 + 4 \times 2 - 6 3 - 8

Moltiplica

4

e

2

per ottenere

8

.

- 10 + 8 - 6 3 - 8

E

- 10

e

8

per ottenere

- 2

.

- 2 - 6 3 - 8

Calcola

3 - 8

e ottieni

- 2

.

- 2 - 6 (- 2)

Moltiplica

- 6

e

- 2

per ottenere

12

.

- 2 + 12

E

- 2

e

12

per ottenere

10

.

10

Scomponi in fattori

2 \times 5

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Quiz

5 problemi simili a:

2 \cdot 3 - 125 + 4 \cdot 532 - 6 \cdot 3 - 8

Problemi simili da ricerca Web

1 - 1 + 1 - 1 + \dots 1 - 1 + 1

https://math.stackexchange.com/questions/441473/the-value-of-sqrt1-sqrt1-sqrt1-sqrt1-cdots-sqrt1-sqrt11

First of all let's assume the series is convergent. Looking for fixed points we have:

x = 1 - 1 + x

Now we will try to solve this equation. First squaring both sides:

1 - x^{2} = 1 + x ((1 - x) (1 + x))^{2} = 1 + x

5 + 11 + 19 + 29 + 41 + \dots

https://math.stackexchange.com/questions/3080127/find-the-sum-sqrt5-sqrt11-sqrt19-sqrt29-sqrt41-cdots

We may adopt the technique for Ramanujan's infinite radical . Let

p (x) = x^{2} + 3 x + 1

F : [0, \infty) \to [0, \infty)

F (x) = p (x) + p (x + 1) + p (x + 2) + \dots

How do you simplify

(2 \cdot 2) + (2 \cdot - 2) + (0 \cdot 0)

https://socratic.org/questions/how-do-you-simplify-sqrt-2-sqrt-2-sqrt-2-sqrt-2-0-0

= 0

(2 \cdot 2)

(2 \cdot - 2)

(0 \cdot 0)

1! 2! 3! \dots n! < 3

https://math.stackexchange.com/questions/2593066/how-to-prove-sqrt1-sqrt2-sqrt3-sqrt-cdots-sqrtn-3

n > 0

s_{n} = d e f lo g ⎝ ⎛ 1! 2! 3! \dots n! ⎠ ⎞ = \sum_{k = 1}^{n} \frac{l o g ( k ! )}{2 ^{k}} = \sum_{k = 1}^{n} \frac{1}{2 ^{k}} \sum_{j = 1}^{k} lo g (j)

Ramanujan's Infinite Root

https://math.stackexchange.com/questions/2381181/ramanujans-infinite-root

There's no contradiction, there's just ill-defined terms. The row

3 = 1 + 2 \cdot 1 + 3 \cdot 1 + 4 \cdot 36

is correct, but the following

⋮

3 = 1 + 2 \cdot 1 + 3 \cdot 1 + 4 \cdot 1 + \dots

Field Show that F is a field under + and

\cdot

{a + b 3} ∣ a, b \in Q}

https://math.stackexchange.com/questions/2423511/field-show-that-f-is-a-field-under-and-cdot-and-f-a-b-sqrt3-a

The axiom you linked to are those of a vector space , not those for a field. It is true (but it is probably not your intention) that

F

is a vector space with scalar field

Q

F

Condividi

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Copia

Copiato negli Appunti

2\left(-5\right)+4\sqrt[5]{32}-6\sqrt[3]{-8}

Calcola \sqrt[3]{-125} e ottieni -5.

-10+4\sqrt[5]{32}-6\sqrt[3]{-8}

Moltiplica 2 e -5 per ottenere -10.

-10+4\times 2-6\sqrt[3]{-8}

Calcola \sqrt[5]{32} e ottieni 2.

-10+8-6\sqrt[3]{-8}

Moltiplica 4 e 2 per ottenere 8.

-2-6\sqrt[3]{-8}

E -10 e 8 per ottenere -2.

-2-6\left(-2\right)

Calcola \sqrt[3]{-8} e ottieni -2.

-2+12

Moltiplica -6 e -2 per ottenere 12.

10

E -2 e 12 per ottenere 10.

Esempi

Equazione quadratica

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

Equazione lineare

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

Equazione simultanea

{8 x + 2 y = 46 7 x + 3 y = 47

Differenziazione

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}