Risolvi (u+3)(u-6) | Microsoft Math Solver

Calcola

(u - 6) (u + 3)

Espandi

u^{2} - 3 u - 18

Quiz

Polynomial

5 problemi simili a:

(u + 3) (u - 6)

Problemi simili da ricerca Web

How do you find the product

(u + 3) (u - 3)

https://socratic.org/questions/how-do-you-find-the-product-u-3-u-3

See explanation. Explanation: To find a product of 2 algebraic sums you have to multiply each term of one sum by each term of the other and then reduce the like terms.

(u + 3) (u - 3) = u^{2} - 3 u + 3 u - 9 = u^{2} - 9

show that under the transformation

w = \frac{( 2 z + 3 )}{( z - 4 )}

,the circle

x^{2} + y^{2} = 4 x

is transformed into the straight line

4 u + 3 = 0

in the w plane [closed]

https://math.stackexchange.com/questions/2018126/show-that-under-the-transformation-w-frac2z3z%e2%88%924-the-circle-x2y2

The given circle is

(x - 2)^{2} + y^{2} = 4

, so take any element

z = (x, y) \sim x + i y

in it and apply to it

w

w (z) : = \frac{2 z + 3}{z - 4} = \frac{2 x + 3 + 2 i y}{x - 4 + i y} \cdot \frac{x - 4 - i y}{x - 4 - i y} = \frac{( 2 x ^{2} - 5 x - 1 2 + 2 y ^{2} ) - 1 1 y i}{( x - 4 ) ^{2} + y ^{2}}

...

Finding generator for group

https://math.stackexchange.com/questions/2069891/finding-generator-for-group

I'm back-interpreting some of your notation, as the question is imprecise at the moment. But I think that having a reasoned-out answer would be helpful. Firstly, a group

G

is (roughly) a set of ...

Help Understanding Fields

https://math.stackexchange.com/questions/401065/help-understanding-fields

The statement you are trying to prove is, indeed, not true if the field has characteristic

2

. If

u = (1, 0)

and

v = (0, 1)

then

u

and

v

are linearly independent but

u + v = u - v = (1, 1)

Composition of systems of equations

https://math.stackexchange.com/questions/396079/composition-of-systems-of-equations

...

Understanding Bayes' Theorem

https://math.stackexchange.com/questions/401389/understanding-bayes-theorem

As Tharsis pointed out, and was clarified in the comments, it is all of sets of the given by

(A \cap B_{i}), 1 \leq i \leq n

that are pairwise disjoint.

(A \cap B_{i}) \cap (A \cap B_{j}) = \emptyset, \forall i, j, s.t. 1 \leq i, j \leq n and i \neq = j

...

Copia

Copiato negli Appunti

u^{2}-6u+3u-18

Applica la proprietà distributiva moltiplicando ogni termine di u+3 per ogni termine di u-6.

u^{2}-3u-18

Combina -6u e 3u per ottenere -3u.

u^{2}-6u+3u-18

Applica la proprietà distributiva moltiplicando ogni termine di u+3 per ogni termine di u-6.

u^{2}-3u-18

Combina -6u e 3u per ottenere -3u.

Esempi

Equazione quadratica

x^{2} - 4 x - 5 = 0

Trigonometria

4 sin θ cos θ = 2 sin θ

Equazione lineare

y = 3 x + 4

Aritmetica

699 * 533

Matrice

[2534] [2 - 1 0135]

Equazione simultanea

{8 x + 2 y = 46 7 x + 3 y = 47

Differenziazione

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

Integrazione

\int_{0}^{1} x e^{- x^{2}} d x

Limiti

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}

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