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Minimo comune multiplo
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Esponenti
Radicali
Algebra
Combinazione di termini simili
Risolvere una variabile
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Espandi
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Equazioni di secondo grado
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Sistemi di equazioni
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Elenco
Trova θ
\theta =\frac{\sqrt{3}}{2}\approx 0.866025404
θ
=
2
3
≈
0
.
8
6
6
0
2
5
4
0
4
Assegna θ
\theta ≔\frac{\sqrt{3}}{2}
θ
:
=
2
3
Grafico
Quiz
Arithmetic
5 problemi simili a:
\theta = \frac { \sqrt { 3 } } { 2 }
θ
=
2
3
Problemi simili da ricerca Web
Alternative of finding theta when sin \theta and cos \theta are given
Alternative of finding theta when sin
θ
and cos
θ
are given
https://math.stackexchange.com/questions/929514/alternative-of-finding-theta-when-sin-theta-and-cos-theta-are-given
\sin\theta=\frac{\sqrt3}2=\sin\frac\pi3\implies\theta=n\pi+(-1)^n\frac\pi3 where n is any integer Set n=2s+1,(odd) =2s(even) one by one Again, \cos\theta=-\frac12=-\cos\frac\pi3=\cos\left(\pi-\frac\pi3\right) ...
sin
θ
=
2
3
=
sin
3
π
⟹
θ
=
n
π
+
(
−
1
)
n
3
π
where
n
is any integer Set
n
=
2
s
+
1
,
(odd)
=
2
s
(even) one by one Again,
cos
θ
=
−
2
1
=
−
cos
3
π
=
cos
(
π
−
3
π
)
...
Delta-method for the convergence in distribution of a_n\left(h(\bar X_n) - h(\theta) - b_n\right) when h'(\theta)=0
Delta-method for the convergence in distribution of
a
n
(
h
(
X
ˉ
n
)
−
h
(
θ
)
−
b
n
)
when
h
′
(
θ
)
=
0
https://math.stackexchange.com/questions/2377042/delta-method-for-the-convergence-in-distribution-of-a-n-lefth-bar-x-n-h-t
The so-called delta-method stems from two basic results: By the usual CLT, \sqrt{n}(\bar X_n-\theta)\to\sigma_\theta Z in distribution, where Z is standard normal and \sigma_\theta^2=\mathrm{var}(X_1) ...
The so-called delta-method stems from two basic results: By the usual CLT,
n
(
X
ˉ
n
−
θ
)
→
σ
θ
Z
in distribution, where
Z
is standard normal and
σ
θ
2
=
v
a
r
(
X
1
)
...
Proof convergence of vectors
Proof convergence of vectors
https://math.stackexchange.com/questions/2948414/proof-convergence-of-vectors
I give here both if part and only if part. Let \{\overrightarrow a_k\}_k converges to \overrightarrow a in R^n . Then using norm ||.|| of R^n we can say that given any \epsilon > 0 ...
I give here both if part and only if part. Let
{
a
k
}
k
converges to
a
in
R
n
. Then using norm
∣
∣
.
∣
∣
of
R
n
we can say that given any
ϵ
>
0
...
How to analyze (-1)^{\left \lfloor n\theta \right \rfloor} (in which \theta is an irrational number)?
How to analyze
(
−
1
)
⌊
n
θ
⌋
(in which
θ
is an irrational number)?
https://math.stackexchange.com/questions/2986901/how-to-analyze-1-left-lfloor-n-theta-right-rfloor-in-which-theta
This is a very interesting problem. Throughout this proof, let \rho(x,z)=\sum_{n=1}^{x}(-1)^{\left\lfloor\frac{n}{\varphi}+z\right\rfloor}, where x \in \mathbb{N} and z\in \mathbb{R} , ...
This is a very interesting problem. Throughout this proof, let
ρ
(
x
,
z
)
=
∑
n
=
1
x
(
−
1
)
⌊
φ
n
+
z
⌋
,
where
x
∈
N
and
z
∈
R
, ...
Find an Unbiased Estimator of a Function of a Parameter [duplicate]
Find an Unbiased Estimator of a Function of a Parameter [duplicate]
https://math.stackexchange.com/q/2643604
Let \hat{\beta}=\frac{1-\hat \theta}{\sqrt{3n}}. Then as you have shown E\hat{\beta}=\frac{1-\theta}{\sqrt{3n}}. Hence \hat{\beta} is an unbiased estimator of \frac{1-\theta}{\sqrt{3n}} ...
Let
β
^
=
3
n
1
−
θ
^
.
Then as you have shown
E
β
^
=
3
n
1
−
θ
.
Hence
β
^
is an unbiased estimator of
3
n
1
−
θ
...
Approximation of irrational numbers?
Approximation of irrational numbers?
https://math.stackexchange.com/questions/1364605/approximation-of-irrational-numbers
No. If \varphi = (\sqrt{5}+1)/2 (which is a root of x^2 - x - 1) and F_n are the Fibonacci numbers, |F_n - \varphi F_{n-1}| goes to 0 exponentially. Take a_n = F_{n+k} for sufficiently ...
No. If
φ
=
(
5
+
1
)
/
2
(which is a root of
x
2
−
x
−
1
) and
F
n
are the Fibonacci numbers,
∣
F
n
−
φ
F
n
−
1
∣
goes to
0
exponentially. Take
a
n
=
F
n
+
k
for sufficiently ...
Altri Elementi
Condividi
Copia
Copiato negli Appunti
Esempi
Equazione quadratica
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometria
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Equazione lineare
y = 3x + 4
y
=
3
x
+
4
Aritmetica
699 * 533
6
9
9
∗
5
3
3
Matrice
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Equazione simultanea
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Differenziazione
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integrazione
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Limiti
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
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