Microsoft Math Solver
Risolvi
Esercizio
Scarica
Solve
Practice
Argomenti
Pre-Algebra
Significato
Modalità
Il più grande fattore comune
Minimo comune multiplo
Ordine delle operazioni
Frazioni
Frazioni miste
Scomposizione in fattori primi
Esponenti
Radicali
Algebra
Combinazione di termini simili
Risolvere una variabile
Fattore
Espandi
Calcolo delle frazioni
Equazioni lineari
Equazioni di secondo grado
Disparità
Sistemi di equazioni
Matrici
Trigonometria
Semplificare
Calcolare
Grafici
Risolvi equazioni
Analisi matematica
Derivate
Integrali
Limiti
Calcolatrice algebrica
Calcolatrice trigonometrica
Calcolo differenziale
Calcolatrice di matrici
Scarica
Argomenti
Pre-Algebra
Significato
Modalità
Il più grande fattore comune
Minimo comune multiplo
Ordine delle operazioni
Frazioni
Frazioni miste
Scomposizione in fattori primi
Esponenti
Radicali
Algebra
Combinazione di termini simili
Risolvere una variabile
Fattore
Espandi
Calcolo delle frazioni
Equazioni lineari
Equazioni di secondo grado
Disparità
Sistemi di equazioni
Matrici
Trigonometria
Semplificare
Calcolare
Grafici
Risolvi equazioni
Analisi matematica
Derivate
Integrali
Limiti
Calcolatrice algebrica
Calcolatrice trigonometrica
Calcolo differenziale
Calcolatrice di matrici
Risolvi
algebra
Trigonometria
statistiche
Analisi matematica
matrici
variabili
Elenco
Trova A,.C,.B,.a,.b
b=C
b
=
C
Quiz
Complex Number
5 problemi simili a:
\left. \begin{array} { l } { A ^ {C} = B }\\ { a = C }\\ { \text{Solve for } b \text{ where} } \\ { b = a } \end{array} \right.
A
C
=
B
a
=
C
Solve for
b
where
b
=
a
Problemi simili da ricerca Web
Relationship between eigenvalues of A^TA and B=\left[\begin{array}{cc} 0 & A^T\\ A & 0\end{array}\right]
Relationship between eigenvalues of
A
T
A
and
B
=
[
0
A
A
T
0
]
https://math.stackexchange.com/questions/2014959/relationship-between-eigenvalues-of-ata-and-b-left-beginarraycc-0-a
Since \mathrm A^{\top} \mathrm A is positive semidefinite, its eigenvalues, \mu_1, \dots, \mu_n, are nonnegative. The characteristic polynomial of \mathrm B is \det (s \mathrm I_{2n} - \mathrm B) = \det \begin{bmatrix} s \mathrm I_{n} & -\mathrm A^{\top}\\ -\mathrm A & s \mathrm I_{n} \end{bmatrix} = \det (s^2 \mathrm I_{n} - \mathrm A^{\top} \mathrm A) ...
Since
A
⊤
A
is positive semidefinite, its eigenvalues,
μ
1
,
…
,
μ
n
, are nonnegative. The characteristic polynomial of
B
is
det
(
s
I
2
n
−
B
)
=
det
[
s
I
n
−
A
−
A
⊤
s
I
n
]
=
det
(
s
2
I
n
−
A
⊤
A
)
...
Sufficient condition for the block matrix \big(\begin{smallmatrix} B & A^T \\ A & 0 \end{smallmatrix} \big) to be invertible
Sufficient condition for the block matrix
(
B
A
A
T
0
)
to be invertible
https://math.stackexchange.com/questions/1027138/sufficient-condition-for-the-block-matrix-big-beginsmallmatrix-b-at-a
Note that \ker A = {\cal R}Z. Suppose Bu + A^T v =0, Au = 0. Then u \in \ker A= {\cal R} Z, hence u = Zw for some w. Then Z^T B Zw + Z^T A^T v = Z^T B Zw + (AZ)^T v = Z^T B Zw = 0. Hence w=0 ...
Note that
ker
A
=
R
Z
. Suppose
B
u
+
A
T
v
=
0
,
A
u
=
0
. Then
u
∈
ker
A
=
R
Z
, hence
u
=
Z
w
for some
w
. Then
Z
T
B
Z
w
+
Z
T
A
T
v
=
Z
T
B
Z
w
+
(
A
Z
)
T
v
=
Z
T
B
Z
w
=
0
. Hence
w
=
0
...
Cholesky factor when adding a row and column to already factorized matrix
Cholesky factor when adding a row and column to already factorized matrix
https://math.stackexchange.com/q/955874
To make this work, you should explicitly assume that a^tA^{-1}a<1; otherwise, the bordered matrix B:=\begin{bmatrix}A & a\\a^t & 1\end{bmatrix} would not be positive definite anymore (and ...
To make this work, you should explicitly assume that
a
t
A
−
1
a
<
1
; otherwise, the bordered matrix
B
:
=
[
A
a
t
a
1
]
would not be positive definite anymore (and ...
inverse of 2\times2 block matrix
inverse of
2
×
2
block matrix
https://math.stackexchange.com/q/1678502
One of the formulas here does not involve D^{-1}
One of the formulas here does not involve
D
−
1
Solve the Non-Homogeneous System y'=Cy+b(t)
Solve the Non-Homogeneous System
y
′
=
C
y
+
b
(
t
)
https://math.stackexchange.com/q/2801318
Let V= \begin{bmatrix} 1 & 1 \\ 1 & -1 \end{bmatrix} and note that C = V \begin{bmatrix} -1 & 0 \\ 0 & -3 \end{bmatrix} V^{-1} and so e^{Ct} = V \begin{bmatrix} e^{-t} & 0 \\ 0 & e^{-3t} \end{bmatrix} V^{-1} ...
Let
V
=
[
1
1
1
−
1
]
and note that
C
=
V
[
−
1
0
0
−
3
]
V
−
1
and so
e
C
t
=
V
[
e
−
t
0
0
e
−
3
t
]
V
−
1
...
Solving systems of ODE'S in the form \dot{\overrightarrow{u}}=A\overrightarrow{u}+\overrightarrow{b}
Solving systems of ODE'S in the form
u
˙
=
A
u
+
b
https://math.stackexchange.com/questions/2034180/solving-systems-of-odes-in-the-form-dot-overrightarrowu-a-overrightarrow
You can use the method of undetermined coefficients or educated guessing to find a particular solution. Since 0 is not an eigenvalue of A and \vec b is constant, look for a particular solution ...
You can use the method of undetermined coefficients or educated guessing to find a particular solution. Since
0
is not an eigenvalue of
A
and
b
is constant, look for a particular solution ...
Altri Elementi
Condividi
Copia
Copiato negli Appunti
Esempi
Equazione quadratica
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometria
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Equazione lineare
y = 3x + 4
y
=
3
x
+
4
Aritmetica
699 * 533
6
9
9
∗
5
3
3
Matrice
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Equazione simultanea
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Differenziazione
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integrazione
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Limiti
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
Torna a inizio pagina