Leysa tanθ=

$$\tan \theta =$$

Diffra með hliðsjón af θ

$$\frac{1}{\left(\cos(\theta )\right)^{2}}$$

Skref með afleiðslureglu fyrir hlutatölu

Nota skilgreiningu tangens.

$$\frac{\mathrm{d}}{\mathrm{d}\theta }(\frac{\sin(\theta )}{\cos(\theta )})$$

Fyrir hver tvö diffranleg föll er afleiða hlutfalls tveggja falla samnefnarinn sinnum afleiða teljarans mínus teljarinn sinnum afleiða samnefnarans og deilt í útkomuna samnefnaranum í öðru veldi.

$$\frac{\cos(\theta )\frac{\mathrm{d}}{\mathrm{d}\theta }(\sin(\theta ))-\sin(\theta )\frac{\mathrm{d}}{\mathrm{d}\theta }(\cos(\theta ))}{\left(\cos(\theta )\right)^{2}}$$

Afleiða sin(\theta ) er cos(\theta ) og afleiða cos(\theta ) er−sin(\theta ).

$$\frac{\cos(\theta )\cos(\theta )-\sin(\theta )\left(-\sin(\theta )\right)}{\left(\cos(\theta )\right)^{2}}$$

Einfaldaðu.

$$\frac{\left(\cos(\theta )\right)^{2}+\left(\sin(\theta )\right)^{2}}{\left(\cos(\theta )\right)^{2}}$$

Notaðu pýþagórska aljöfnu.

$$\frac{1}{\left(\cos(\theta )\right)^{2}}$$

Nota skilgreiningu sekants.

$$\left(\sec(\theta )\right)^{2}$$

Meta

$$\tan(\theta )$$