Leysa sqrt{196}-sqrt[3]{216} | Microsoft stærðfræði leysa

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https://socratic.org/questions/how-do-you-simplify-sqrt11-3-sqrt11-3

https://www.quora.com/How-do-you-find-the-value-of-sqrt-3-%2B-sqrt-3-sqrt-3-%2B

https://www.quora.com/Why-is-sqrt-1-*-sqrt-1-1-and-not-1

https://socratic.org/questions/how-do-you-use-de-moivre-s-theorem-to-simplify-z-2-cos-5pi-4-isin-5pi-4-5-to-16r

https://math.stackexchange.com/questions/1881822/show-that-19-5-sqrt32-8-sqrt34-is-a-unit-in-mathbbz-sqrt32

https://www.quora.com/I-know-the-conjugate-of-sqrt-a-is-sqrt-a-and-the-conjugate-of-sqrt-a-sqrt-b-is-sqrt-a-+-sqrt-b-But-there-are-some-irrational-number-numbers-that-I-dont-know-how-to-find-the-conjugate-of-For-example-what-is-the-conjugate-of-sqrt-3-sqrt-2-+1-and-4+2-sqrt-3-3-+-sqrt-3-9

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14-\sqrt[3]{216}

Reiknaðu kvaðratrót af 196 og fáðu 14.

14-6

Reiknaðu \sqrt[3]{216} og fáðu 6.

8

Dragðu 6 frá 14 til að fá út 8.

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