Selesaikan -1/12 | Microsoft Math Solver

Evaluasi

- \frac{1}{1 2} \approx - 0.083333333

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Faktor

\frac{- 1}{2 ^{2} \cdot 3} \approx - 0.083333333

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Kuis

5 soal serupa dengan:

- 1 / 12

Soal yang Mirip dari Pencarian Web

A model train, with a mass of

4 k g

, is moving on a circular track with a radius of

7 m

. If the train's rate of revolution changes from

\frac{1}{1 2} H z

https://socratic.org/questions/a-model-train-with-a-mass-of-4-kg-is-moving-on-a-circular-track-with-a-radius-of-4

The change in centripetal force is

= 69.1 N

Explanation: The centripetal force is

F = m r ω^{2}

m = 4 k g

Find the tangent line of

\frac{x ^{2}}{y + 1} + x y^{2} = 4

y = 1

y < x

https://math.stackexchange.com/q/409126

You have forgotten that the

x y^{2}

term requires a product rule when differentiating

sec θ = - \frac{1 3}{1 2}

cos \frac{θ}{2}

\frac{π}{2} < θ < π

. The official answer differs from mine.

https://math.stackexchange.com/questions/3117696/if-sec-theta-frac1312-then-find-cos-frac-theta2-where-frac

The answer they gave

(\frac{5 2 6}{2 6})

is the value for

sin \frac{θ}{2} = \pm \frac{1 - cos θ}{2}

however they're looking for

cos \frac{θ}{2} = \pm \frac{1 + cos θ}{2}

Does the number meet the condition of the equation?

https://math.stackexchange.com/questions/2755310/does-the-number-meet-the-condition-of-the-equation

The conditions of the equation are

x + 3 > 0

12 x + 1 > 0 .

which could be replaced by

x > \frac{- 1}{1 2}

\frac{- 6 1}{1 2} < \frac{- 1}{1 2}

and is not a solution.

Question about laurent series

https://math.stackexchange.com/questions/986139/question-about-laurent-series

z

, right? One of them being a constant times

z^{- 1}

, right? Just use geometric series:

(z - 1)^{- 1} = - 1 / (1 - z) = - \sum_{n \geq 0} z^{n}

, so that the troublesome part is

- \sum_{n \geq - 1} z^{n}

Quadratic inequality where

x \in R

https://math.stackexchange.com/q/2828823

I don't see a mistake in your solution. I think your solution is right: Let

\frac{x}{x ^{2} - 5 x + 9} = y .

Hence, the equation

y x^{2} - (5 y + 1) x + 9 y = 0

has real roots. For

y = 0

x = 0

y \neq = 0

Bagikan

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-\frac{1}{12}

Pecahan \frac{-1}{12} dapat ditulis kembali sebagai -\frac{1}{12} dengan mengekstrak tanda negatif.

Masalah Serupa

\frac{4}{1 2} - \frac{9}{7}

\frac{4}{1 2} \times \frac{9}{8}

\frac{4}{1 2} \div \frac{9}{8}

\frac{4}{1 2} + \frac{9}{8}

\frac{4}{1 2} + \frac{9}{8} \times \frac{1 5}{3} - \frac{2 6}{1 0}

\frac{1}{8} + 2 (\frac{9}{7}) \div \frac{1 5}{3}