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Daftar
Evaluasi
-5
−
5
Lihat langkah-langkah penyelesaian
Langkah Solusi
1/x-2-1/x-3
1
/
x
−
2
−
1
/
x
−
3
Kurangi 3 dari -2 untuk mendapatkan -5.
Kurangi
3
dari
−
2
untuk mendapatkan
−
5
.
\frac{1}{x}-5-\frac{1}{x}
x
1
−
5
−
x
1
Kurangi \frac{1}{x} dari \frac{1}{x} untuk mendapatkan 0.
Kurangi
x
1
dari
x
1
untuk mendapatkan
0
.
-5
−
5
Faktor
\left(-1\right)\times 5
(
−
1
)
×
5
Grafik
Kuis
Polynomial
5 soal serupa dengan:
1/x-2-1/x-3
1
/
x
−
2
−
1
/
x
−
3
Soal yang Mirip dari Pencarian Web
1/x-2-1/x-3
1
/
x
−
2
−
1
/
x
−
3
http://www.tiger-algebra.com/drill/1/x-2-1/x-3/
1/x-2-1/x-3 Final result : -5 Step by step solution : Step 1 : 1 Simplify — x Equation at the end of step 1 : 1 1 ((— - 2) - —) - 3 x x Step 2 : 1 Simplify — x Equation at the end of step 2 ...
1/x-2-1/x-3 Final result : -5 Step by step solution : Step 1 : 1 Simplify — x Equation at the end of step 1 : 1 1 ((— - 2) - —) - 3 x x Step 2 : 1 Simplify — x Equation at the end of step 2 ...
Simplify \frac{1}{x-2}-\frac{1}{x+2}
Simplify
x
−
2
1
−
x
+
2
1
https://math.stackexchange.com/questions/857184/simplify-frac1x-2-frac1x2
\frac{1}{x-2}-\frac{1}{x+2} = \frac{x+2}{(x-2)(x+2)}- \frac{x-2}{(x+2)(x-2)} = \frac{x+2 - (x-2)}{(x+2)(x-2)} = \frac{x+2 - x + 2 }{(x+2)(x-2)} = \frac{4}{(x+2)(x-2)} = \frac{4}{x^2-4}. First step ...
x
−
2
1
−
x
+
2
1
=
(
x
−
2
)
(
x
+
2
)
x
+
2
−
(
x
+
2
)
(
x
−
2
)
x
−
2
=
(
x
+
2
)
(
x
−
2
)
x
+
2
−
(
x
−
2
)
=
(
x
+
2
)
(
x
−
2
)
x
+
2
−
x
+
2
=
(
x
+
2
)
(
x
−
2
)
4
=
x
2
−
4
4
. First step ...
How does -\frac{1}{x-2} + \frac{1}{x-3} become \frac{1}{2-x} - \frac{1}{3-x}
How does
−
x
−
2
1
+
x
−
3
1
become
2
−
x
1
−
3
−
x
1
https://math.stackexchange.com/questions/1275071/how-does-frac1x-2-frac1x-3-become-frac12-x-frac13-x
Each of the terms was multiplied by \frac{-1}{-1}, which is really equal to 1, so it's a "legal" thing to do: -\dfrac{1}{x - 2} + \dfrac{1}{x - 3} = -\dfrac{(-1)1}{(-1)(x - 2)} + \dfrac{(-1)1}{(-1)(x - 3)} ...
Each of the terms was multiplied by
−
1
−
1
, which is really equal to
1
, so it's a "legal" thing to do:
−
x
−
2
1
+
x
−
3
1
=
−
(
−
1
)
(
x
−
2
)
(
−
1
)
1
+
(
−
1
)
(
x
−
3
)
(
−
1
)
1
...
How do you solve \displaystyle\frac{{x}}{{{x}-{2}}}-\frac{{1}}{{{x}-{3}}}={\left({1}\right)} ?
How do you solve
x
−
2
x
−
x
−
3
1
=
(
1
)
?
https://socratic.org/questions/how-do-you-solve-x-x-2-1-x-3-1
\displaystyle{x}={4} Explanation: Multiply through by \displaystyle{\left({x}-{2}\right)}{\left({x}-{3}\right)} \displaystyle\Rightarrow\frac{{{x}{\left({x}-{2}\right)}{\left({x}-{3}\right)}}}{{{x}-{2}}}-\frac{{{\left({x}-{2}\right)}{\left({x}-{3}\right)}}}{{{x}-{3}}}={\left({x}-{2}\right)}{\left({x}-{3}\right)} ...
x
=
4
Explanation: Multiply through by
(
x
−
2
)
(
x
−
3
)
⇒
x
−
2
x
(
x
−
2
)
(
x
−
3
)
−
x
−
3
(
x
−
2
)
(
x
−
3
)
=
(
x
−
2
)
(
x
−
3
)
...
1/125:3=x:12
1
/
1
2
5
:
3
=
x
:
1
2
https://www.tiger-algebra.com/drill/1/125:3=x:12/
1/125:3=x:12 One solution was found : x = 4/125 = 0.032 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...
1/125:3=x:12 One solution was found : x = 4/125 = 0.032 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...
1/x+2/3-x=4
1
/
x
+
2
/
3
−
x
=
4
https://www.tiger-algebra.com/drill/1/x_2/3-x=4/
1/x+2/3-x=4 Two solutions were found : x =(10-√136)/-6=5/-3+1/3√ 34 = 0.277 x =(10+√136)/-6=5/-3-1/3√ 34 = -3.610 Rearrange: Rearrange the equation by subtracting what is to the right of the ...
1/x+2/3-x=4 Two solutions were found : x =(10-√136)/-6=5/-3+1/3√ 34 = 0.277 x =(10+√136)/-6=5/-3-1/3√ 34 = -3.610 Rearrange: Rearrange the equation by subtracting what is to the right of the ...
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\frac{1}{x}-5-\frac{1}{x}
Kurangi 3 dari -2 untuk mendapatkan -5.
-5
Kurangi \frac{1}{x} dari \frac{1}{x} untuk mendapatkan 0.
Masalah Serupa
\frac{4}{x-2} - \frac{5}{x+1}
x
−
2
4
−
x
+
1
5
\frac{24}{x-3} + \frac{15}{3x+1}
x
−
3
2
4
+
3
x
+
1
1
5
\frac{7x}{x-6} \div \frac{x}{3{(x-6)}^{2}}
x
−
6
7
x
÷
3
(
x
−
6
)
2
x
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