Selesaikan 24/x-3+15/3x+1 | Microsoft Math Solver

Evaluasi

\frac{3 ( 2 9 x - 7 )}{( x - 3 ) ( 3 x + 1 )}

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Langkah-langkah Solusi Singkat

\frac{2 4}{x - 3} + \frac{1 5}{3 x + 1}

Untuk menambahkan atau mengurangi ekspresi, perluas untuk menyamakan penyebutnya. Kelipatan persekutuan terkecil dari

x - 3

dan

3 x + 1

adalah

(x - 3) (3 x + 1)

. Kalikan

\frac{2 4}{x - 3}

kali

\frac{3 x + 1}{3 x + 1}

. Kalikan

\frac{1 5}{3 x + 1}

kali

\frac{x - 3}{x - 3}

.

\frac{2 4 ( 3 x + 1 )}{( x - 3 ) ( 3 x + 1 )} + \frac{1 5 ( x - 3 )}{( x - 3 ) ( 3 x + 1 )}

Karena

\frac{2 4 ( 3 x + 1 )}{( x - 3 ) ( 3 x + 1 )}

dan

\frac{1 5 ( x - 3 )}{( x - 3 ) ( 3 x + 1 )}

memiliki penyebut yang sama, tambahkan bilangan dengan menambahkan pembilangnya.

\frac{2 4 ( 3 x + 1 ) + 1 5 ( x - 3 )}{( x - 3 ) ( 3 x + 1 )}

Kalikan bilangan berikut

24 (3 x + 1) + 15 (x - 3)

.

\frac{7 2 x + 2 4 + 1 5 x - 4 5}{( x - 3 ) ( 3 x + 1 )}

Gabungkan seperti suku di

72 x + 24 + 15 x - 45

.

\frac{8 7 x - 2 1}{( x - 3 ) ( 3 x + 1 )}

Luaskan

(x - 3) (3 x + 1)

.

\frac{8 7 x - 2 1}{3 x ^{2} - 8 x - 3}

Faktor

\frac{3 ( 2 9 x - 7 )}{( x - 3 ) ( 3 x + 1 )}

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Grafik

Kuis

5 soal serupa dengan:

\frac{2 4}{x - 3} + \frac{1 5}{3 x + 1}

Soal yang Mirip dari Pencarian Web

(5 x / (3 x + 7)) + (2 / (3 + x)) = 1

https://www.tiger-algebra.com/drill/(5x/(3x_7))_(2/(3_x))=1/

(5x/(3x+7))+(2/(3+x))=1 Two solutions were found : x = -7/2 = -3.500 x = 1 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the ...

3 / x - 1 - 5 / 3 x + 1 = 1

https://www.tiger-algebra.com/drill/3/x-1-5/3x_1=1/

3/x-1-5/3x+1=1 Two solutions were found : x =(3-√189)/-10=3/-10+3/10√ 21 = 1.075 x =(3+√189)/-10=3/-10-3/10√ 21 = -1.675 Rearrange: Rearrange the equation by subtracting what is to the right ...

(5 / 4) x + (1 / 8) x = (7 / 8) + x

https://www.tiger-algebra.com/drill/(5/4)x_(1/8)x=(7/8)_x/

(5/4)x+(1/8)x=(7/8)+x One solution was found : x = 7/3 = 2.333 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the ...

(5 / (x + 1)) - (1 / x) - 8 = 0

https://www.tiger-algebra.com/drill/(5/(x_1))-(1/x)-8=0/

(5/(x+1))-(1/x)-8=0 Two solutions were found : x =(4-√-16)/-16=1/-4+i/4= -0.2500-0.2500i x =(4+√-16)/-16=1/-4-i/4= -0.2500+0.2500i Step by step solution : Step 1 : 1 Simplify — x Equation at ...

How do you solve

\frac{1}{2} (x - 3) = \frac{1}{3} (2 x + 1)

https://socratic.org/questions/how-do-you-solve-1-2-x-3-1-3-2x-1

Tessalsifi Jun 1, 2015

\frac{x}{2} - \frac{3}{2} = \frac{2 x}{3} + \frac{1}{3}

We are going to put it all on six by multiplying both denominators and ...

How do you solve

\frac{1}{3} x + \frac{1}{2} = \frac{1 1}{1 2}

https://socratic.org/questions/how-do-you-solve-1-3x-1-2-11-12

: x = \frac{5}{4} = 1.25

. Explanation: Multiplying the eqn. throughout by

12

12 \cdot \frac{1}{3} x + 12 \cdot \frac{1}{2} = 12 \cdot (\frac{1 1}{1 2})

Bagikan

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Salin

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\frac{24\left(3x+1\right)}{\left(x-3\right)\left(3x+1\right)}+\frac{15\left(x-3\right)}{\left(x-3\right)\left(3x+1\right)}

Untuk menambahkan atau mengurangi ekspresi, perluas untuk menyamakan penyebutnya. Kelipatan persekutuan terkecil dari x-3 dan 3x+1 adalah \left(x-3\right)\left(3x+1\right). Kalikan \frac{24}{x-3} kali \frac{3x+1}{3x+1}. Kalikan \frac{15}{3x+1} kali \frac{x-3}{x-3}.

\frac{24\left(3x+1\right)+15\left(x-3\right)}{\left(x-3\right)\left(3x+1\right)}

Karena \frac{24\left(3x+1\right)}{\left(x-3\right)\left(3x+1\right)} dan \frac{15\left(x-3\right)}{\left(x-3\right)\left(3x+1\right)} memiliki penyebut yang sama, tambahkan bilangan dengan menambahkan pembilangnya.

\frac{72x+24+15x-45}{\left(x-3\right)\left(3x+1\right)}

Kalikan bilangan berikut 24\left(3x+1\right)+15\left(x-3\right).

\frac{87x-21}{\left(x-3\right)\left(3x+1\right)}

Gabungkan seperti suku di 72x+24+15x-45.

\frac{87x-21}{3x^{2}-8x-3}

Luaskan \left(x-3\right)\left(3x+1\right).

Masalah Serupa

\frac{4}{x - 2} - \frac{5}{x + 1}

\frac{2 4}{x - 3} + \frac{1 5}{3 x + 1}

\frac{7 x}{x - 6} \div \frac{x}{3 ( x - 6 ) ^{2}}