Cari nilai y
y=\left(x+4\right)^{2}
Cari nilai x (complex solution)
x=-\left(\sqrt{y}+4\right)
x=\sqrt{y}-4
Cari nilai x
x=-\left(\sqrt{y}+4\right)
x=\sqrt{y}-4\text{, }y\geq 0
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y=x^{2}+8x+16
Gunakan teorema binomial \left(a+b\right)^{2}=a^{2}+2ab+b^{2} untuk menjabarkan \left(x+4\right)^{2}.
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