x d y + y d x + ( 1 + x ^ { 2 } ) d x + x ^ { 2 } \sin y d y = 0
Cari nilai x
\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x=\frac{\sqrt{\left(\sin(dy^{2})\right)^{2}-8yd^{2}-4d^{2}}-\sin(dy^{2})}{2d}\text{; }x=-\frac{\sqrt{\left(\sin(dy^{2})\right)^{2}-8yd^{2}-4d^{2}}+\sin(dy^{2})}{2d}\text{, }&d\neq 0\text{ and }\left(\sin(dy^{2})\right)^{2}-8yd^{2}-4d^{2}\geq 0\\x\in \mathrm{R}\text{, }&d=0\end{matrix}\right,
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Trigonometry
5 soal serupa dengan:
x d y + y d x + ( 1 + x ^ { 2 } ) d x + x ^ { 2 } \sin y d y = 0
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