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Daftar
Evaluasi
21411
2
1
4
1
1
Lihat langkah-langkah penyelesaian
Langkah Solusi
793 \times 27
7
9
3
×
2
7
Kalikan 793 dan 27 untuk mendapatkan 21411.
Kalikan
7
9
3
dan
2
7
untuk mendapatkan
2
1
4
1
1
.
21411
2
1
4
1
1
Faktor
3^{3}\times 13\times 61
3
3
×
1
3
×
6
1
Kuis
Arithmetic
793 \times 27
7
9
3
×
2
7
Soal yang Mirip dari Pencarian Web
How do you simplify \displaystyle{\left({3}\times{6}\right)}-{5} using order of operations?
How do you simplify
(
3
×
6
)
−
5
using order of operations?
https://socratic.org/questions/how-do-you-simplify-3-times-6-5-using-order-of-operations
Use BIDMAS! Explanation: Brackets Indicies Division Multiplication Addition Subtraction So away to figure out the question is to follow the rule of BIDMAS! The question is: \displaystyle{\left({3}\times{6}\right)}-{5} ...
Use BIDMAS! Explanation: Brackets Indicies Division Multiplication Addition Subtraction So away to figure out the question is to follow the rule of BIDMAS! The question is:
(
3
×
6
)
−
5
...
In how many ways can a number be written as a product of two different factors?
In how many ways can a number be written as a product of two different factors?
https://math.stackexchange.com/q/1930477
You are almost right. As already observed in the comments, note that, calling k_1, k_2, k_3... the exponents of each prime number in the factorization, if your final product (k_1+1)(k_2+1)(k_3+1)... ...
You are almost right. As already observed in the comments, note that, calling
k
1
,
k
2
,
k
3
.
.
.
the exponents of each prime number in the factorization, if your final product
(
k
1
+
1
)
(
k
2
+
1
)
(
k
3
+
1
)
.
.
.
...
Boruta score goes to minus infinity
Boruta score goes to minus infinity
https://stats.stackexchange.com/questions/109211/boruta-score-goes-to-minus-infinity
Boruta works by re-applying VIM and progressively removing attributes which seem irrelevant; when an attribute becomes removed, it obviously stops getting importance scores so they are set to -Inf ...
Boruta works by re-applying VIM and progressively removing attributes which seem irrelevant; when an attribute becomes removed, it obviously stops getting importance scores so they are set to -Inf ...
Divisors of 25^2+98^2
Divisors of
2
5
2
+
9
8
2
https://math.stackexchange.com/questions/1804333/divisors-of-252982
The trick here is the useful identity a^4+4b^4=(a^2+2ab+2b^2)(a^2-2ab+2b^2). In this case we have a=5,b=7, so we get the factorisation (25+70+98)(25-70+98)=193\cdot53. It is now easy to check ...
The trick here is the useful identity
a
4
+
4
b
4
=
(
a
2
+
2
a
b
+
2
b
2
)
(
a
2
−
2
a
b
+
2
b
2
)
. In this case we have
a
=
5
,
b
=
7
, so we get the factorisation
(
2
5
+
7
0
+
9
8
)
(
2
5
−
7
0
+
9
8
)
=
1
9
3
⋅
5
3
. It is now easy to check ...
Elementary counting: multiplication?
Elementary counting: multiplication?
https://math.stackexchange.com/questions/2313275/elementary-counting-multiplication
You would add the numbers of choices in case they exclude each other. E.g. if you could choose between Bob on one of three days, or Lea on one of two days. B1\text{ or }B2\text{ or }B3\text{ or }L1\text{ or }L2. ...
You would add the numbers of choices in case they exclude each other. E.g. if you could choose between Bob on one of three days, or Lea on one of two days.
B
1
or
B
2
or
B
3
or
L
1
or
L
2
.
...
Why is 9 \times 11{\dots}12 = 100{\dots}08?
Why is
9
×
1
1
…
1
2
=
1
0
0
…
0
8
?
https://math.stackexchange.com/questions/2107382/why-is-9-times-11-dots12-100-dots08
The repunit , R_k = \overbrace{111\ldots 111}^{k \text{ ones}} , can be written as R_k = \dfrac{10^k-1}{9} Your nice pattern corresponds to 9\times (R_k+1) = (10^k-1)+9 = 10^k+8
The repunit ,
R
k
=
1
1
1
…
1
1
1
k
ones
, can be written as
R
k
=
9
1
0
k
−
1
Your nice pattern corresponds to
9
×
(
R
k
+
1
)
=
(
1
0
k
−
1
)
+
9
=
1
0
k
+
8
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21411
Kalikan 793 dan 27 untuk mendapatkan 21411.
Contoh
Persamaan kuadrat
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometri
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Persamaan linear
y = 3x + 4
y
=
3
x
+
4
Aritmetika
699 * 533
6
9
9
∗
5
3
3
Matriks
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Persamaan simultan
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Diferensial
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integral
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Limit
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
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