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Diferensial w.r.t. θ
6\theta ^{5}
6
θ
5
Lihat langkah-langkah penyelesaian
Langkah Menggunakan Definisi Turunan
\theta ^ { 6 } =
θ
6
=
Turunan dari ax^{n} nax^{n-1}.
Turunan dari
a
x
n
n
a
x
n
−
1
.
6\theta ^{6-1}
6
θ
6
−
1
Kurangi 1 dari 6.
Kurangi
1
dari
6
.
6\theta ^{5}
6
θ
5
Evaluasi
\theta ^{6}
θ
6
Grafik
Kuis
Arithmetic
5 soal serupa dengan:
\theta ^ { 6 } =
θ
6
=
Soal yang Mirip dari Pencarian Web
Using the MSE criterion, which is a better estimator for \Theta^2?
Using the MSE criterion, which is a better estimator for
Θ
2
?
https://math.stackexchange.com/q/191043
I just give an answer as the persons visiting the question shouldnt go through all the conversations. Without imposing another conditions on the parameter \Theta or the types of these two ...
I just give an answer as the persons visiting the question shouldnt go through all the conversations. Without imposing another conditions on the parameter
Θ
or the types of these two ...
A question about modular forms in SAGE
A question about modular forms in SAGE
https://math.stackexchange.com/questions/135472/a-question-about-modular-forms-in-sage
Thank you for reading my book. I am not an expert in Sage, but I can tell you what I had in mind when I wrote that problem. The goal of the exercise is to work with \Theta^6 replicating what is done ...
Thank you for reading my book. I am not an expert in Sage, but I can tell you what I had in mind when I wrote that problem. The goal of the exercise is to work with
Θ
6
replicating what is done ...
Containing an open set = being an open set?
Containing an open set = being an open set?
https://math.stackexchange.com/questions/2184858/containing-an-open-set-being-an-open-set
Saying \Theta' is open is much stronger as saying that it contains some open rectangles. It says that for all \theta \in \Theta', there is an open rectangle R with \theta \in R \subset \Theta' ...
Saying
Θ
′
is open is much stronger as saying that it contains some open rectangles. It says that for all
θ
∈
Θ
′
, there is an open rectangle
R
with
θ
∈
R
⊂
Θ
′
...
Find asymptotic variance MLE heavy tailed distribution
Find asymptotic variance MLE heavy tailed distribution
https://math.stackexchange.com/q/1244514
Your MLE for \theta does not seem correct. If \boldsymbol x = (x_1, \ldots, x_n) is an iid sample drawn from a X \sim \operatorname{Pareto}(1,\theta) distribution with density f_X(x) = \theta x^{-\theta-1} \mathbb{1}(x > 1) ...
Your MLE for
θ
does not seem correct. If
x
=
(
x
1
,
…
,
x
n
)
is an iid sample drawn from a
X
∼
P
a
r
e
t
o
(
1
,
θ
)
distribution with density
f
X
(
x
)
=
θ
x
−
θ
−
1
1
(
x
>
1
)
...
Extensions of Ramanujan's Cos/Cosh Identity
Extensions of Ramanujan's Cos/Cosh Identity
https://math.stackexchange.com/questions/517409/extensions-of-ramanujans-cos-cosh-identity
It will be helpful to start from an explanation of the origin and the proof of the Ramanujan identity. These are hidden (not very deeply) in the theory of elliptic functions. Indeed, Jacobi elliptic ...
It will be helpful to start from an explanation of the origin and the proof of the Ramanujan identity. These are hidden (not very deeply) in the theory of elliptic functions. Indeed, Jacobi elliptic ...
Expectation maximization when support of likelihood is parameterized
Expectation maximization when support of likelihood is parameterized
https://stats.stackexchange.com/q/318089
I think g(\theta;\theta^0) may have a mistake. If 0 < \theta_2 < 4, then g(\theta;\theta^0)=\frac{1}{4} \int_0^{\theta_2} \ln \frac{1}{\theta_2} dx_{32} = -\frac{\theta_2}{4} \ln \theta_2. ...
I think
g
(
θ
;
θ
0
)
may have a mistake. If
0
<
θ
2
<
4
, then
g
(
θ
;
θ
0
)
=
4
1
∫
0
θ
2
ln
θ
2
1
d
x
3
2
=
−
4
θ
2
ln
θ
2
.
...
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6\theta ^{6-1}
Turunan dari ax^{n} nax^{n-1}.
6\theta ^{5}
Kurangi 1 dari 6.
Contoh
Persamaan kuadrat
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometri
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Persamaan linear
y = 3x + 4
y
=
3
x
+
4
Aritmetika
699 * 533
6
9
9
∗
5
3
3
Matriks
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Persamaan simultan
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Diferensial
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integral
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Limit
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
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