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Daftar
Cari nilai x
x=5
x
=
5
Grafik
Kedua Sisi Grafik dalam 2D
Grafik dalam 2D
Kuis
Algebra
\log_{ 2 }({ 32 }) = x
lo
g
2
(
3
2
)
=
x
Soal yang Mirip dari Pencarian Web
How do you solve \displaystyle{\log}_{{2}}{32}={x} ?
How do you solve
lo
g
2
3
2
=
x
?
https://socratic.org/questions/how-do-you-solve-log-2-32-x
\displaystyle{x}={5} Explanation: The logarithmic expression can be exponentiated with a base of \displaystyle{2} : \displaystyle{2}^{{{{\log}_{{2}}{32}}}}={2}^{{x}} The \displaystyle{2}^{{x}} ...
x
=
5
Explanation: The logarithmic expression can be exponentiated with a base of
2
:
2
l
o
g
2
3
2
=
2
x
The
2
x
...
How do you solve \displaystyle{{\log}_{{3}}{32}}={x} ?
How do you solve
lo
g
3
3
2
=
x
?
https://socratic.org/questions/how-do-you-solve-log-3-32-x
This is already 'solved' in that \displaystyle{x}={{\log}_{{3}}{32}} but you can use the change of base formula to find: \displaystyle{x}=\frac{{\log{{\left({32}\right)}}}}{{\log{{\left({3}\right)}}}}=\frac{{\ln{{\left({32}\right)}}}}{{\ln{{\left({3}\right)}}}}\approx{3.15465} ...
This is already 'solved' in that
x
=
lo
g
3
3
2
but you can use the change of base formula to find:
x
=
lo
g
(
3
)
lo
g
(
3
2
)
=
ln
(
3
)
ln
(
3
2
)
≈
3
.
1
5
4
6
5
...
How do you write \displaystyle{{\log}_{{4}}{\left({32}\right)}}={x} in exponential form?
How do you write
lo
g
4
(
3
2
)
=
x
in exponential form?
https://socratic.org/questions/how-do-you-write-log-4-32-x-in-exponential-form
I found: \displaystyle{32}={4}^{{x}} Explanation: You can use the definition of log: \displaystyle{{\log}_{{a}}{b}}={x}\to{b}={a}^{{x}} so basically \displaystyle{4} "pushes up" \displaystyle{x} ...
I found:
3
2
=
4
x
Explanation: You can use the definition of log:
lo
g
a
b
=
x
→
b
=
a
x
so basically
4
"pushes up"
x
...
How do you solve \displaystyle{{\log}_{{2}}{3}}={x} ?
How do you solve
lo
g
2
3
=
x
?
https://socratic.org/questions/how-do-you-solve-log-2-3-x
\displaystyle\therefore{x}\approx{1.585} Explanation: \displaystyle{{\log}_{{2}}{3}}={x} \displaystyle\frac{{\log{{3}}}}{{\log{{2}}}}={x} : Use the change of base formula \displaystyle{{\log}_{{b}}{a}}=\frac{{\log{{a}}}}{{\log{{b}}}} ...
∴
x
≈
1
.
5
8
5
Explanation:
lo
g
2
3
=
x
lo
g
2
lo
g
3
=
x
: Use the change of base formula
lo
g
b
a
=
lo
g
b
lo
g
a
...
How do you write \displaystyle{{\log}_{{3}}{27}}={x} in exponential form?
How do you write
lo
g
3
2
7
=
x
in exponential form?
https://socratic.org/questions/how-do-you-write-log-3-27-x-in-exponential-form
\displaystyle{27}={3}^{{x}} Explanation: Using the \displaystyle\text{law of logarithms} \displaystyle\text{Reminder}{\left({\mid}\overline{{\underline{{{\left(\frac{{a}}{{a}}\right)}{\left({{\log}_{{b}}{a}}={n}\Leftrightarrow{a}={b}^{{n}}\right)}{\left(\frac{{a}}{{a}}\right)}{\mid}}}}}\right)} ...
2
7
=
3
x
Explanation: Using the
law of logarithms
Reminder
(
∣
(
a
a
)
(
lo
g
b
a
=
n
⇔
a
=
b
n
)
(
a
a
)
∣
)
...
How do you solve \displaystyle{{\log}_{{3}}{75}}={2}{x} ?
How do you solve
lo
g
3
7
5
=
2
x
?
https://socratic.org/questions/how-do-you-solve-log-3-75-2x
P dilip_k Mar 27, 2016 \displaystyle{{\log}_{{3}}{75}}={2}{x}\Rightarrow{3}^{{{2}{x}}}={75}\Rightarrow{9}^{{x}}={75}\Rightarrow{x}{\log{{9}}}={\log{{75}}} \displaystyle\Rightarrow{x}=\frac{{\log{{75}}}}{{{\log{{3}}}^{{2}}}}=\frac{{\log{{75}}}}{{{2}{\log{{3}}}}}
P dilip_k Mar 27, 2016
lo
g
3
7
5
=
2
x
⇒
3
2
x
=
7
5
⇒
9
x
=
7
5
⇒
x
lo
g
9
=
lo
g
7
5
⇒
x
=
lo
g
3
2
lo
g
7
5
=
2
lo
g
3
lo
g
7
5
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Persamaan kuadrat
{ x } ^ { 2 } - 4 x - 5 = 0
x
2
−
4
x
−
5
=
0
Trigonometri
4 \sin \theta \cos \theta = 2 \sin \theta
4
sin
θ
cos
θ
=
2
sin
θ
Persamaan linear
y = 3x + 4
y
=
3
x
+
4
Aritmetika
699 * 533
6
9
9
∗
5
3
3
Matriks
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
[
2
5
3
4
]
[
2
−
1
0
1
3
5
]
Persamaan simultan
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
{
8
x
+
2
y
=
4
6
7
x
+
3
y
=
4
7
Diferensial
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
d
x
d
(
x
−
5
)
(
3
x
2
−
2
)
Integral
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
∫
0
1
x
e
−
x
2
d
x
Limit
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}
x
→
−
3
lim
x
2
+
2
x
−
3
x
2
−
9
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